分割字符串后将值插入表中

我想将值插入员工表中。 这些值是字符串格式的~分开

E.g: AA~B~123

我使用以下函数分割它

CREATE FUNCTION [db_owner].[FN_Split] (@String varchar(8000), @Delimiter char(1))
   returns @temptable TABLE (items varchar(8000))        
   as        
   begin        
       declare @idx int        
        declare @slice varchar(8000)        

        select @idx = 1        
            if len(@String)<1 or @String is null  return        

       while @idx!= 0        
       begin        
           set @idx = charindex(@Delimiter,@String)        
           if @idx!=0        
               set @slice = left(@String,@idx - 1)        
           else        
              set @slice = @String        

           if(len(@slice)>0)   
               insert into @temptable(Items) values(@slice)        

           set @String = right(@String,len(@String) - @idx)        
           if len(@String) = 0 break        
       end    
   return        
   end 

现在我得到输出为

SELECT * FROM db_owner.FN_Split('AA~B~123','~')

Output

items
______
AA
B
123

现在我被困在这里了

如何在员工表中插入以上值？？？

like

insert into employee (name,add,phone)
values('AA','B','123');

请指导。

尝试过这个但不起作用

insert into employee
SELECT * FROM db_owner.FN_Split('AA~BB~CC','~')

ERROR

Msg 213, Level 16, State 1, Line 1
Column name or number of supplied values does not match table definition.

您正在使用字符串拆分函数，该函数将项目作为行返回。您需要一个将它们作为列返回的函数。

或者您可以直接在查询中执行此操作。也许是这样的。

declare @S varchar(10) = 'AA~B~123'

select left(@S, T1.Pos - 1) as Col1,
       substring(@S, T1.Pos+1, T2.Pos-T1.Pos-1) as Col2,
       substring(@S, T2.Pos+1, len(@S)-T2.Pos) as Col3
from (select charindex('~', @S)) as T1(Pos)
cross apply (select charindex('~', @S, T1.Pos+1)) as T2(Pos)

Result:

Col1       Col2       Col3
---------- ---------- ----------
AA         B          123

这是在 SQL Server 2000 中运行的版本

declare @S varchar(10) 
set @S = 'AA~B~123'

select left(@S, T.Pos1 - 1) as Col1,
       substring(@S, T.Pos1+1, T.Pos2-T.Pos1-1) as Col2,
       substring(@S, T.Pos2+1, len(@S)-T.Pos2) as Col3
from (select T.Pos1,
             charindex('~', @S, T.Pos1+1) as Pos2
      from (select charindex('~', @S) as Pos1) as T
     ) as T