如何从 Deno 运行任意 shell 命令？

我想从 Deno 运行任意 bash 命令，就像使用child_process在节点中。这在 Deno 中可能吗？

Deno 1.28.0 添加了一个新的 API 来运行 shell 命令：Deno.Command https://deno.land/api?s=Deno.Command (--allow-run需要许可）

let cmd = new Deno.Command("echo", { args: ["hello world"] });
let { code, stdout, stderr } = await cmd.output();
// stdout & stderr are a Uint8Array
console.log(new TextDecoder().decode(stdout)); // hello world

更高级的用法：

const command = new Deno.Command(Deno.execPath(), {
  args: [
    "eval",
    "console.log('Hello World')",
  ],
  stdin: "piped",
  stdout: "piped",
});
const child = command.spawn();

// open a file and pipe the subprocess output to it.
child.stdout.pipeTo(
  Deno.openSync("output", { write: true, create: true }).writable,
);

// manually close stdin
child.stdin.close();
const status = await child.status;

const s = await c.status;
console.log(s);

该 API 取代了已弃用的Deno.run

旧答案：

为了运行 shell 命令，您必须使用Deno.run，这需要--allow-run权限。

有一个持续讨论 https://github.com/denoland/deno/issues/3378 to use --allow-all而不是运行子进程

以下将输出到stdout.

// --allow-run
const process = Deno.run({
  cmd: ["echo", "hello world"]
});

// Close to release Deno's resources associated with the process.
// The process will continue to run after close(). To wait for it to
// finish `await process.status()` or `await process.output()`.
process.close();

如果你想存储输出，你必须设置stdout/stderr to "piped"

const process = Deno.run({
  cmd: ["echo", "hello world"], 
  stdout: "piped",
  stderr: "piped"
});


const output = await process.output() // "piped" must be set
const outStr = new TextDecoder().decode(output);

/* 
const error = await p.stderrOutput();
const errorStr = new TextDecoder().decode(error); 
*/

process.close();