我刚刚编写了以下 C++ 函数来以编程方式确定系统安装了多少 RAM。它有效,但在我看来应该有一种更简单的方法来做到这一点。我错过了什么吗?
getRAM()
{
FILE* stream = popen("head -n1 /proc/meminfo", "r");
std::ostringstream output;
int bufsize = 128;
while( !feof(stream) && !ferror(stream))
{
char buf[bufsize];
int bytesRead = fread(buf, 1, bufsize, stream);
output.write(buf, bytesRead);
}
std::string result = output.str();
std::string label, ram;
std::istringstream iss(result);
iss >> label;
iss >> ram;
return ram;
}
首先,我正在使用popen("head -n1 /proc/meminfo")
从系统获取 meminfo 文件的第一行。该命令的输出看起来像
内存总计:775280 kB
一旦我得到了输出istringstream
,很容易将其标记化以获取我想要的信息。有没有更简单的方法来读取此命令的输出?是否有标准 C++ 库调用来读取系统 RAM 量?
在Linux上,您可以使用该函数sysinfo
它在以下结构中设置值:
#include <sys/sysinfo.h>
int sysinfo(struct sysinfo *info);
struct sysinfo {
long uptime; /* Seconds since boot */
unsigned long loads[3]; /* 1, 5, and 15 minute load averages */
unsigned long totalram; /* Total usable main memory size */
unsigned long freeram; /* Available memory size */
unsigned long sharedram; /* Amount of shared memory */
unsigned long bufferram; /* Memory used by buffers */
unsigned long totalswap; /* Total swap space size */
unsigned long freeswap; /* swap space still available */
unsigned short procs; /* Number of current processes */
unsigned long totalhigh; /* Total high memory size */
unsigned long freehigh; /* Available high memory size */
unsigned int mem_unit; /* Memory unit size in bytes */
char _f[20-2*sizeof(long)-sizeof(int)]; /* Padding for libc5 */
};
如果你想只使用 C++ 的函数来做到这一点(我会坚持sysinfo
),我建议采用 C++ 方法std::ifstream
and std::string
:
unsigned long get_mem_total() {
std::string token;
std::ifstream file("/proc/meminfo");
while(file >> token) {
if(token == "MemTotal:") {
unsigned long mem;
if(file >> mem) {
return mem;
} else {
return 0;
}
}
// Ignore the rest of the line
file.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
return 0; // Nothing found
}
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