我正在尝试可变地借用可变变量。Deref
and DerefMut
实施用于Foo
,但编译失败:
use std::ops::{Deref, DerefMut};
struct Foo;
impl Deref for Foo {
type Target = FnMut() + 'static;
fn deref(&self) -> &Self::Target {
unimplemented!()
}
}
impl DerefMut for Foo {
fn deref_mut(&mut self) -> &mut Self::Target {
unimplemented!()
}
}
fn main() {
let mut t = Foo;
t();
}
error[E0596]: cannot borrow immutable borrowed content as mutable
--> src/main.rs:20:5
|
20 | t();
| ^ cannot borrow as mutable
较新版本的编译器有更新的错误消息:
error[E0596]: cannot borrow data in a dereference of `Foo` as mutable
--> src/main.rs:20:5
|
20 | t();
| ^ cannot borrow as mutable
|
= help: trait `DerefMut` is required to modify through a dereference, but it is not implemented for `Foo`
This is 一个已知问题 https://github.com/rust-lang/rust/issues/26186关于如何通过以下方式推断功能特征Deref
。作为解决方法,您需要通过执行可变重新借用来显式获取可变引用:
let mut t = Foo;
(&mut *t)();
或通过致电DerefMut::deref_mut
:
let mut t = Foo;
t.deref_mut()();
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