我通常通过给出批处理命令 %~dp0 来组合多个 csv 文件来获取当前工作目录。
但是我在获取当前工作目录时遇到了与号（&）符号，这使得批处理文件在“&”之后中断，表示&之后的路径不被识别为内部或外部命令。
你们中的任何人都可以帮助我修改下面的脚本来识别 & 并将其替换为 ^& （因为这可以转义 & 并运行批处理文件）。感谢您的任何建议；
这是我的代码：
@echo off
ECHO Set working directory
pushd %~dp0 - How to escape & in this line???
ECHO Deleting existing combined file
del combined.csv
setlocal ENABLEDELAYEDEXPANSION
REM set count to 1
set cnt=1
REM for each file that matches *.csv
for %%i in (*.csv) do (
REM if count is 1 it's the first time running
if !cnt!==1 (
REM push the entire file complete with header into combined.csv - this will also create combined.csv
for /f "delims=" %%j in ('type "%%i"') do echo %%j >> combined.csv
REM otherwise, make sure we're not working with the combined file and
) else if %%i NEQ combined.csv (
REM push the file without the header into combined.csv
for /f "skip=1 delims=" %%j in ('type "%%i"') do echo %%j >> combined.csv
)
REM increment count by 1
set /a cnt+=1
)
cmd \k
将引号括起来%~dp0应该足够了：
...
pushd "%~dp0"
...
顺便说一句，我不明白你为什么使用pushd。你不popd在你的代码中的任何地方pushd似乎没用。如果我明白的话ECHO Set working directory正确，你应该更换pushd with CD %~dp0.
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