交叉过滤查询

是否可以过滤以数组作为值的交叉过滤数据集？

例如，假设我有以下数据集：

var data = [
  {
    bookname: "the joy of clojure",
    authors: ["Michael Fogus", "Chris Houser"],
    tags: ["clojure", "lisp"]
  },
  {
    bookname: "Eloquent Ruby",
    authors: ["Russ Olsen"],
    tags: ["ruby"]
  },
  {
    bookname: "Design Patterns in Ruby",
    authors: ["Russ Olsen"],
    tags: ["design patterns", "ruby"]
  }
];

有没有一种简单的方法来访问带有特定标签的书籍？还有有特定作者的书吗？到目前为止，我理解如何使用 crossfilter 的方式让我做了这样的事情：

var filtered_data = crossfilter(data);
var tags = filtered_data.dimension(function(d) {return d.tags});
var tag = tags.group();

然后当我访问分组时（像这样）：

tag.all()

我明白了：

[{key: ["clojure", "lisp"], value: 1}, 
 {key: ["design patterns", "ruby"], value: 1}, 
 {key: ["ruby"], value: 1}]

当我宁愿这样的时候：

[{key: "ruby", value: 2}, 
 {key: "clojure", value: 1}, 
 {key: "lisp", value: 1},
 {key: "design patterns", value: 1}]

我已在下面的代码中添加了注释。大图：使用reduce函数。

var data = ...
var filtered_data = crossfilter(data);
var tags = filtered_data.dimension(function(d) {return d.tags});

tags.groupAll().reduce(reduceAdd, reduceRemove, reduceInitial).value()

注意我是如何使用的全部分组()代替group()b/c 我们希望我们的reduce 函数（定义如下）在一组而不是3 组上运行。

现在，reduce 函数应该如下所示：

/*
 v is the row in the dataset

 p is {} for the first execution (passed from reduceInitial). 
 For every subsequent execution it is the value returned from reduceAdd of the prev row
*/
function reduceAdd(p, v) {
  v.tags.forEach (function(val, idx) {
     p[val] = (p[val] || 0) + 1; //increment counts
  });
  return p;
}

function reduceRemove(p, v) {
   //omitted. not useful for demonstration
}

function reduceInitial() {
  /* this is how our reduce function is seeded. similar to how inject or fold 
   works in functional languages. this map will contain the final counts 
   by the time we are done reducing our entire data set.*/
  return {};  
}