火花 >= 3.0.0
从 Spark 3.0.0 开始,这可以在不使用 UDF 的情况下完成。
from pyspark.ml.functions import vector_to_array
(df
.withColumn("xs", vector_to_array("vector")))
.select(["word"] + [col("xs")[i] for i in range(3)]))
## +-------+-----+-----+-----+
## | word|xs[0]|xs[1]|xs[2]|
## +-------+-----+-----+-----+
## | assert| 1.0| 2.0| 3.0|
## |require| 0.0| 2.0| 0.0|
## +-------+-----+-----+-----+
火花
一种可能的方法是在 RDD 之间进行转换:
from pyspark.ml.linalg import Vectors
df = sc.parallelize([
("assert", Vectors.dense([1, 2, 3])),
("require", Vectors.sparse(3, {1: 2}))
]).toDF(["word", "vector"])
def extract(row):
return (row.word, ) + tuple(row.vector.toArray().tolist())
df.rdd.map(extract).toDF(["word"]) # Vector values will be named _2, _3, ...
## +-------+---+---+---+
## | word| _2| _3| _4|
## +-------+---+---+---+
## | assert|1.0|2.0|3.0|
## |require|0.0|2.0|0.0|
## +-------+---+---+---+
另一种解决方案是创建 UDF:
from pyspark.sql.functions import udf, col
from pyspark.sql.types import ArrayType, DoubleType
def to_array(col):
def to_array_(v):
return v.toArray().tolist()
# Important: asNondeterministic requires Spark 2.3 or later
# It can be safely removed i.e.
# return udf(to_array_, ArrayType(DoubleType()))(col)
# but at the cost of decreased performance
return udf(to_array_, ArrayType(DoubleType())).asNondeterministic()(col)
(df
.withColumn("xs", to_array(col("vector")))
.select(["word"] + [col("xs")[i] for i in range(3)]))
## +-------+-----+-----+-----+
## | word|xs[0]|xs[1]|xs[2]|
## +-------+-----+-----+-----+
## | assert| 1.0| 2.0| 3.0|
## |require| 0.0| 2.0| 0.0|
## +-------+-----+-----+-----+
对于 Scala 等效项,请参阅Spark Scala:如何将 Dataframe[vector] 转换为 DataFrame[f1:Double, ..., fn: Double)] https://stackoverflow.com/q/38110038.