c# 拼接Json串的几种方法

C#定义多行字符串的方式

在定义的前面加上@符号：

1             string aa = @"asdfsdfsd
2                         fsdsfsdfsdfsdfsdfsdfs
3                         safasfsadfsdfasfsfsdfsd ";  

在C#中拼接字符串有几种方法

1. 利用  JsonConvert.SerializeObject方法 (Nuget获取Newtonsoft.Json Package)

 1             string uid = "22";
 2 
 3             var abcObject = new
 4             {
 5                 AccessKey = 11,
 6                 CustomerNo = uid,
 7                 mc = "33",
 8                 qd = "44",
 9                 mr = "55",
10                 insertDate = DateTime.Now
11             };
12             string serJson = JsonConvert.SerializeObject(abcObject);  

2. 利用StringBuilder

1             StringBuilder str = new StringBuilder();
2             str.Append("{");
3             str.Append("AccessKey:\"" + 11 + "\",");
4             str.Append("mc:\"" + 22 + "\",");
5             str.Append("qd:\"" + 33 + "\"");
6             str.Append("}");
7             string serJson = str.ToString();  

3. 直接拼接字符串

1         string serJon = "{AccessKey:\"" + 11 + "\",mc:\"" + 22 + "\"}";  

4. 利用StringFormat

1             string mc = "22";
2             string id = "11";
3             string serJson = string.Format("[{{ AccessKey:\"{0}\",mc:\"{1}\"}},{{ AccessKey:\"{2}\",mc:\"{3}\"}}]", id, mc, "33", "44");