您可以尝试编组:
将类的布局声明为顺序(并注意,您将需要使用Pack = 1
):
[StructLayout(LayoutKind.Sequential, Pack = 1)]
class Data
{
public int _int1;
public int _int2;
public short _short1;
public long _long1;
}
将字节编组到 Data 类的新实例中:
var bytes = new byte[] { 1, 0, 0, 0, 2, 0, 0, 0, 3, 0, 4, 0, 0, 0, 0, 0, 0, 0 };
GCHandle gcHandle = GCHandle.Alloc(bytes, GCHandleType.Pinned);
var data = (Data)Marshal.PtrToStructure(gcHandle.AddrOfPinnedObject(), typeof(Data));
gcHandle.Free();
// Now data should contain the correct values.
Console.WriteLine(data._int1); // Prints 1
Console.WriteLine(data._int2); // Prints 2
Console.WriteLine(data._short1); // Prints 3
Console.WriteLine(data._long1); // Prints 4
为了方便起见,您可以在 Data 上编写一个静态方法来进行转换:
[StructLayout(LayoutKind.Sequential, Pack = 1)]
class Data
{
public int _int1;
public int _int2;
public short _short1;
public long _long1;
public static Data FromBytes(byte[] bytes)
{
GCHandle gcHandle = GCHandle.Alloc(bytes, GCHandleType.Pinned);
var data = (Data)Marshal.PtrToStructure(gcHandle.AddrOfPinnedObject(), typeof(Data));
gcHandle.Free();
return data;
}
}
...
var data = Data.FromBytes(new byte[] {1, 0, 0, 0, 2, 0, 0, 0, 3, 0, 4, 0, 0, 0, 0, 0, 0, 0});
如果您确实愿意,可以编写一个显式运算符来从字节数组进行转换,以获取 OP 中的语法。我建议只使用Data.FromBytes()
在我看来,这会更加清晰。
不过,为了完整性:
[StructLayout(LayoutKind.Sequential, Pack = 1)]
class Data
{
public int _int1;
public int _int2;
public short _short1;
public long _long1;
public static explicit operator Data(byte[] bytes)
{
GCHandle gcHandle = GCHandle.Alloc(bytes, GCHandleType.Pinned);
var data = (Data)Marshal.PtrToStructure(gcHandle.AddrOfPinnedObject(), typeof(Data));
gcHandle.Free();
return data;
}
}
...
var data = (Data)new byte[] {1, 0, 0, 0, 2, 0, 0, 0, 3, 0, 4, 0, 0, 0, 0, 0, 0, 0};