我正在使用 Classic Asp 构建对 url 的请求,现在成功了
是我想从函数返回 Request 对象并获取以下内容
问题:
对象不支持此属性或方法,
我该怎么做 ?
Set objSrvHTTP = Server.CreateObject ("Msxml2.ServerXMLHTTP.3.0")
objSrvHTTP.open "POST","Https://",False,"",""
objSrvHTTP.SetRequestHeader "Content-Type", "text/xml"
objSrvHTTP.SetRequestHeader "Authorization", "Basic " & EncodeBase64("[email protected] /cdn-cgi/l/email-protection:f00tball")
objSrvHTTP.SetRequestHeader "dev-t", " MyAccessKey "
objSrvHTTP.SetRequestHeader "Cookie", "ubid-main=172-9288630-2514702; session-id=026-6553457-3334020; session-id-time=1191279600l;"
objSrvHTTP.send
BuildRequest=objSrvHTTP
Thanks
Change
BuildRequest=objSrvHTTP
to
Set BuildRequest=objSrvHTTP
返回对象。
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