我有这个接口,我想从它包含的键类型生成一个新类型。
interface SomeType {
abc: string;
def: number;
ghi: boolean;
}
输入生成:
type SomeOtherType = string | number | boolean
这在打字稿中可能吗?
您可以尝试使用 keyof 运算符进行索引:
interface SomeType {
abc: string;
def: number;
ghi: "sdf";
}
type t = SomeType[keyof SomeType];
The type t will be assumed as a type union that comes from the values of the object:
https://www.typescriptlang.org/play?#code/JYOwLgpgTgZghgYwgAgMoHsC2EAqBPABxQG8AoZZOAIwQC5kBnMKUAcwG5zkATCGekAFdMVaJwqsAFsHoAiBtxizOAX1KkwhFGGQBeNFlxaA2gGsIedDAPZ8RALrsgA https://www.typescriptlang.org/play?#code/JYOwLgpgTgZghgYwgAgMoHsC2EAqBPABxQG8AoZZOAIwQC5kBnMKUAcwG5zkATCGekAFdMVaJwqsAFsHoAiBtxizOAX1KkwhFGGQBeNFlxaA2gGsIedDAPZ8RALrsgA
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