在 C# 中使用时间跨度简化 if else 条件

2023-12-28

我必须创建一份实时报告。为此,我必须为特定日期的每个小时编写条件。在下面的代码中,条件检查当前星期几,然后检查当前时间,并据此生成报告。

protected void sample()
{
    TimeSpan zerothHour = new TimeSpan(00, 0, 0);
    TimeSpan firstHour = new TimeSpan(01, 0, 0);
    TimeSpan secondHour = new TimeSpan(02, 0, 0);
    TimeSpan thirdHour = new TimeSpan(03, 0, 0);
    TimeSpan fourthHour = new TimeSpan(04, 0, 0);
    TimeSpan fifthHour = new TimeSpan(05, 0, 0);
    TimeSpan sixthHour = new TimeSpan(06, 0, 0); 
    // and so on until the twentyfourth hour
    if (DateTime.Today.DayOfWeek == DayOfWeek.Monday)
    {
        if (DateTime.Now.TimeOfDay >= sixthHour && DateTime.Now.TimeOfDay <= seventhHour)
        {
            //MySql query here
            string MyConString = ConfigurationManager.ConnectionStrings["connStr"].ConnectionString;
            MySqlConnection connection = new MySqlConnection(MyConString);
            string agentlogin = "SELECT agentlogin FROM agentdetails WHERE location = 'PNQ10-Pune' AND shift IN('6:00-15-00', '22:00-7:00') AND Mon = 'W'";
            MySqlCommand cmd = new MySqlCommand(agentlogin, connection);
            connection.Open();
            MySqlDataReader rdr = cmd.ExecuteReader();
            while (rdr.Read())
            {
               //lblagentlogin.Text += rdr["agentlogin"] + Environment.NewLine;
                sqlList.Add(Convert.ToString(rdr["agentlogin"]));
            }
        }
        else if(DateTime.Now.TimeOfDay >= seventhHour && DateTime.Now.TimeOfDay <= eigthHour)
        {

        }
        else if (DateTime.Now.TimeOfDay >= eigthHour && DateTime.Now.TimeOfDay <= ninthHour)
        {

        }
        else if (DateTime.Now.TimeOfDay >= ninthHour && DateTime.Now.TimeOfDay <= tenthHour)
        {

        }
        else if (DateTime.Now.TimeOfDay >= tenthHour && DateTime.Now.TimeOfDay <= eleventhHour)
        {

        }
        // and so on for the entire cycle of time
    }
}

上面的代码仅适用于星期一,我也必须在一周的其他六天做同样的事情。当我在每个条件中添加查询时,它会像数百行一样。

有没有更好的方法来完成此任务而无需编写数百行代码?


这对你有用吗?

var sqls = new []
{
    "select x from y",
    "select w from q",
    // etc - 24 options
};

var sql = sqls[DateTime.Now.Hour];

Or even:

var sqls = new Action[]
{
    () => { /* sql for midnight */ },
    () => { /* sql for 1 am */ },
    // etc
    () => { /* sql for 11 pm */ },
};

var sql = sqls[DateTime.Now.Hour];

sql.Invoke();

如果你想DayOfWeek and Hour那么你可以使用这个:

var sqls = new string[][]
{
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
    new [] { "select x from y", "select w from q", },
};

var sql = sqls[(int)DateTime.Now.DayOfWeek][DateTime.Now.Hour];

根据评论和其他答案,这是一种更简洁的方法:

string day = DateTime.Now.DayOfWeek.ToString().Substring(0, 3);

string[] shifts = new []
{
    "('22:00-7:00')",
    "('22:00-7:00', '6:00-15:00')",
    // 24
};

string shift = shifts[DateTime.Now.Hour];

string sql = $"SELECT agentlogin FROM agentdetails WHERE location = 'PNQ10-Pune' AND shift IN {shifts} AND {day} = 'W'";
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)

在 C# 中使用时间跨度简化 if else 条件 的相关文章

随机推荐