Java preg_match 数组

有绳子strng = "<title>text1</title><title>text2</title>";如何获得类似数组

arr[0] = "text1";
arr[1] = "text2";

我尝试使用这个，但结果有，而不是数组text1</title><title>text2

Pattern pattern = Pattern.compile("<title>(.*)</title>");
Matcher matcher = pattern.matcher(strng);
matcher.matches();

虽然我同意使用 XML / HTML 解析器一般来说是更好的选择 http://www.codinghorror.com/blog/2009/11/parsing-html-the-cthulhu-way.html，您的场景很容易用正则表达式解决：

List<String> titles = new ArrayList<String>();
Matcher matcher = Pattern.compile("<title>(.*?)</title>").matcher(strng);
while(matcher.find()){
    titles.add(matcher.group(1));
}

注意非贪婪运算符.*?和使用matcher.find()代替matcher.matches().

参考：

• Pattern> 不情愿的量词 http://download.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html#reluc
• Matcher.find() http://download.oracle.com/javase/6/docs/api/java/util/regex/Matcher.html#find%28%29