我可能会尝试如下操作:
# models.py
class Question(models.Model):
QUESTION_NAMES = (
'Blurb',
'Group Header',
'Group Footer',
'Sub-Group Header',
'Sub-Group Footer',
'Save Button',
'Standard Question',
'Text-Area Question',
'Multiple-Choice Question',
'Standard Sub-Question',
'Multiple-Choice Sub-Question')
QUESTION_VALS = (10, 20, 21, 30,
31, 50, 100, 105, 110,
120, 130)
QUESTION_TYPES = tuple(zip(QUESTION_VALS, QUESTION_NAMES))
# Personal choice here: I never name attribs after Python built-ins:
qtype = models.IntegerField(default=100,choices=QUESTION_TYPES)
以下内容并不像我想象的那样工作
(以下是我对序列化对象列表的原始直觉,但它不起作用。无论如何我将它留在这里,因为它看起来应该起作用。)
好的,我们有一种方法可以自己访问字符串,现在我们只需要序列化它们,为此,我可能会尝试使用ListField
in DRF3 http://www.django-rest-framework.org/api-guide/fields/#listfield,这应该支持source
夸格,我会想?
# serializers.py
from .models import Question
class YourSerializer(ModelSerializer):
names = serializers.ListField(
child=serializers.CharField(max_length=40),
source=Question.QUESTION_NAMES
)
class Meta:
model = Question
fields = ('names', etc.)
以下确实返回结果列表
后备:使用SerializerMethodField
:
from .models import Question
class YourSerializer(serializers.ModelSerializer):
...
names = serializers.SerializerMethodField()
def get_names(self, obj):
return Question.QUESTION_NAMES
class Meta:
model = Question
Demo:
In [1]: q = Question.objects.create()
Out[1]: <Question: Question object>
In [2]: ser = YourSerializer(q)
In [3]: ser.data
Out[3]: {'id': 1, 'names': ['Blurb', 'Group Header', 'Group Footer', 'Sub-Group Header', 'Sub-Group Footer', 'Save Button', 'Standard Question', 'Text-Area Question', 'Multiple-Choice Question', 'Standard Sub-Question', 'Multiple-Choice Sub-Question'], 'qtype': 100}