使用 Java,我试图等待对我正在等待的 Javascript 脚本之一的响应。
我已经发现我可以使用等待响应 https://playwright.dev/java/docs/api/class-page#page-wait-for-response,但是如果在到达 waitForResponse 语句之前脚本已经完成加载,这会导致问题。
有没有办法让我等待脚本完成但前提是尚未收到脚本?
page.waitForResponse("**/*<<Script reference>>*.js", () -> { });
任何帮助将不胜感激!
你需要做的是审核所有流量。
这里有一些例子:
import com.microsoft.playwright.Browser;
import com.microsoft.playwright.BrowserType;
import com.microsoft.playwright.Page;
import com.microsoft.playwright.Playwright;
public class Pw {
public static void main(String[] args) {
try (Playwright playwright = Playwright.create()) {
BrowserType chromium = playwright.chromium();
Browser browser = chromium.launch();
Page page = browser.newPage();
page.onResponse(response -> System.out.println(response.status() + " " + response.url()));
page.navigate("https://playwright.dev/java/docs/network");
browser.close();
}
}
}
OUTPUT:
200 https://playwright.dev/java/docs/network
200 https://playwright.dev/java/assets/css/styles.57a5681f.css
200 https://playwright.dev/java/js/redirection.js
200 https://playwright.dev/java/assets/js/main.bdc3f5b7.js
200 https://playwright.dev/java/assets/js/runtime~main.f37ee5cd.js
200 https://playwright.dev/java/img/playwright-logo.svg
200 https://playwright.dev/java/assets/js/04005ac5.4bff4e91.js
这样你不会错过您的要求.
我希望我能够帮助你。
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