键入任何？没有下标成员

我想从个人资料字典中获取地址，但收到错误“键入任何？没有下标成员”

var address:[[String : Any]] = [["Address": "someLocation", "City": "ABC","Zip" : 123],["Address": "someLocation", "City": "DEF","Zip" : 456]]
var profile:[String : Any] = ["Name": "Mir", "Age": 10, "Addresses": address]
profile["Addresses"][0]     <-----------------type any? has no subscript members

我该如何修复它并获取地址？多谢。

当您使用下标配置文件时"Addresses"，你会得到一个Any实例返回。您选择使用Any在同一数组中容纳各种类型会导致发生类型擦除。您需要将结果转换回其真实类型，[[String: Any]]以便它知道Any实例代表一个Array。然后你就可以给它加上下标：

func f() {
    let address: [[String : Any]] = [["Address": "someLocation", "City": "ABC","Zip" : 123],["Address": "someLocation", "City": "DEF","Zip" : 456]]
    let profile: [String : Any] = ["Name": "Mir", "Age": 10, "Addresses": address]

    guard let addresses = profile["Addresses"] as? [[String: Any]] else {
        // Either profile["Addresses"] is nil, or it's not a [[String: Any]]
        // Handle error here
        return
    }

    print(addresses[0])
}

但这非常笨重，而且首先使用字典并不是一个非常合适的情况。

在这种情况下，如果您的字典具有一组固定的键，那么结构体是更合适的选择。它们是强类型的，因此您不必从Any，它们具有更好的性能，并且更容易合作。尝试这个：

struct Address {
    let address: String
    let city: String
    let zip: Int
}

struct Profile {
    let name: String
    let age: Int
    let addresses: [Address]
}

let addresses = [
    Address(
        address: "someLocation"
        city: "ABC"
        zip: 123
    ),
    Address(
        address: "someLocation"
        city: "DEF"
        zip: 456
    ),
]

let profile = Profile(name: "Mir", age: 10, addresses: addresses)

print(profile.addresses[0]) //much cleaner/easier!