如何将聚合与列名列表一起使用

你如何抽象aggregate在函数中通过传递条件和值列表来总结？

# This works fine:
x <- data.frame(cond1 = sample(letters[1:3], 500, replace=TRUE), 
                cond2 = sample(LETTERS[1:7], 500, replace = TRUE), 
                cond3 = sample(LETTERS[1:4], 500, replace = TRUE), 
                value1 = rnorm(500), 
                value2 = rnorm(500))

aggregate(cbind(value1,value2) ~ cond1 + cond2, data = x, FUN=sum)

需要创建列名称列表：（显示 3 个选项）然后调用该函数：

c1 <- c("cond1","cond2","cond3"); v1 <- c("value1","value2")
c1 <- c("cond2","cond3");         v1 <- c("value2")
c1 <- c("cond3");                 v1 <- c("value1")

aggregate(cbind(v1) ~ c1, data = x, FUN=sum)

我已经审查了许多替代方案，但尚未发现这种抽象的关键。

您可以使用替代接口aggregate，它不使用公式：

c1 <- c("cond1","cond2","cond3")
v1 <- c("value1","value2")
aggregate(x[v1],by=x[c1],FUN=sum)

   cond1 cond2 cond3     value1      value2
1      a     A     A -3.3025839 -0.98304649
2      b     A     A  0.6326985 -3.08677485
3      c     A     A  3.6007853  2.23962265
4      a     B     A -0.5247620 -0.94644740
5      b     B     A  0.9242562  2.48268452
6      c     B     A  6.9215712  0.31512645