如何查找连续相同值的项目作为 Linq 组

var schedules = new List<Item>{
    new Item { Id=1, Name = "S" },
    new Item { Id=2, Name = "P" },
    new Item { Id=3, Name = "X" },
    new Item { Id=4, Name = "X" },
    new Item { Id=5, Name = "P" },
    new Item { Id=6, Name = "P" },
    new Item { Id=7, Name = "P" },
    new Item { Id=8, Name = "S" }
};

我想在新列表中选择相同的值和相同的顺序，如下所示：

var groupedAndSelectedList = new List<List<Item>>{
    new List<Item> {       
        new Item { Id=3, Name = "X" },
        new Item { Id=4, Name = "X" },
    },
    new List<Item> {       
        new Item { Id=5, Name = "P" },
        new Item { Id=6, Name = "P" },
        new Item { Id=7, Name = "P" },
    }
}

如果商品是单一的，例如new Item { Id=3, Name = "A" }我不需要得到它。

分组依据选择列表中的所有 X 或 P 元素。但我想要项目是否位于另一个项目之后或之前。

使用 linq 可以吗？

您在这里寻找的是GroupWhile<T>方法。

信用给用户L.B https://stackoverflow.com/users/932418/l-b的解决方案。去给他原来的答案一个UpDoothttps://stackoverflow.com/a/20469961/30155 https://stackoverflow.com/a/20469961/30155

    var schedules = new List<Item>{
        new Item { Id=1, Name = "S" },
        new Item { Id=2, Name = "P" },
        new Item { Id=3, Name = "X" },
        new Item { Id=4, Name = "X" },
        new Item { Id=5, Name = "P" },
        new Item { Id=6, Name = "P" },
        new Item { Id=7, Name = "P" },
        new Item { Id=8, Name = "S" }
    };

    var results = schedules
        .GroupWhile((preceding, next) => preceding.Name == next.Name) 
        //Group items, while the next is equal to the preceding one
        .Where(s => s.Count() > 1)
        //Only include results where the generated sublist have more than 1 element.
        .ToList();

    foreach (var sublist in results)
    {
        foreach (Item i in sublist)
        {
            Console.WriteLine($"{i.Name} - {i.Id}");
        }
        Console.WriteLine("");
    }

    Console.ReadLine();

您可以将实现作为扩展方法添加到所有IEnumerable<T>像这样。

public static class Extensions
{
    public static IEnumerable<IEnumerable<T>> GroupWhile<T>(this IEnumerable<T> seq, Func<T, T, bool> condition)
    {
        T prev = seq.First();
        List<T> list = new List<T>() { prev };

        foreach (T item in seq.Skip(1))
        {
            if (condition(prev, item) == false)
            {
                yield return list;
                list = new List<T>();
            }
            list.Add(item);
            prev = item;
        }

        yield return list;
    }
}