设置按下后退按钮后返回功能后,React Native WebView 应用程序不会在按后退按钮时退出。我希望当 webview 不在主页上时按后退按钮返回功能,当 webview 位于主页上时然后退出应用程序。
export default class WebView extends Component {
constructor (props) {
super(props);
this.WEBVIEW_REF = React.createRef();
}
componentDidMount() {
BackHandler.addEventListener('hardwareBackPress', this.handleBackButton);
}
componentWillUnmount() {
BackHandler.removeEventListener('hardwareBackPress', this.handleBackButton);
}
handleBackButton = ()=>{
this.WEBVIEW_REF.current.goBack();
return true;
}
onNavigationStateChange(navState) {
this.setState({
canGoBack: navState.canGoBack
});
}
render(){
return (
<WebView
source={{ uri: 'https://stackoverflow.com' }}
ref={this.WEBVIEW_REF}
onNavigationStateChange={this.onNavigationStateChange.bind(this)}
/>
);
}
}
由于您正在管理以下状态canGoBack
inside onNavigationStateChange
功能,改变你的handleBackButton
函数如下,
handleBackButton = () => {
if (this.state.canGoBack) {
this.WEBVIEW_REF.current.goBack();
return true;
}
}
检查下面的完整示例
import React, { Component } from "react";
import { BackHandler } from "react-native";
import { WebView } from "react-native-webview";
export default class App extends Component {
WEBVIEW_REF = React.createRef();
state = {
canGoBack: false,
};
componentDidMount() {
BackHandler.addEventListener("hardwareBackPress", this.handleBackButton);
}
componentWillUnmount() {
BackHandler.removeEventListener("hardwareBackPress", this.handleBackButton);
}
handleBackButton = () => {
if (this.state.canGoBack) {
this.WEBVIEW_REF.current.goBack();
return true;
}
};
onNavigationStateChange = (navState) => {
this.setState({
canGoBack: navState.canGoBack,
});
};
render() {
return (
<WebView
source={{ uri: "https://stackoverflow.com" }}
ref={this.WEBVIEW_REF}
onNavigationStateChange={this.onNavigationStateChange}
/>
);
}
}
希望这对您有帮助。如有疑问,请放心。
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