Jquery find 不适用于 AJAX 返回数据

function openFaceBox(path) {
    $.ajax({
        type: "GET",
        url: path,
        success: function( data ) {
            $.facebox( data ); // data returns html
                    var tableHeight = $(data).find('table').height();
                    console.log( tableHeight ); // Output : 0 (Zero)
        }               
    }); 
}

我的 AJAX 返回 html 如下：

<div id="holder-1">
    <h1>Content 1</h1>
</div>
<div id="holder-2">
    <h1>Content 2</h1>
</div>
<div id="holder-3">
    <h1>Content 3</h1>
</div>
<table>
    <tr>
        <td>abcd</td>
        <td>Some Text Here Some Text Here Some Text Here Some Text Here
            Some Text Here Some Text Here Some Text Here Some Text Here Some Text
            Here Some Text Here Some Text Here Some Text Here Some Text Here Some
            Text Here Some Text Here Some Text Here Some Text Here Some Text Here
            Some Text Here Some Text Here Some Text Here Some Text Here Some Text
            Here</td>
    </tr>
</table>

我不明白为什么.find()不管用。基本上我想找到桌子的高度。如有任何困惑，请告诉我。

Use filter().

console.log($(data).filter('table'));

假设data是一串HTML， 你可以这样做：

$(data).find('table');

这将返回table而不将数据添加到DOM.