您的公式几乎是正确的,但是您必须交换经度和纬度的参数
Console.WriteLine(DistanceAlgorithm.DistanceBetweenPlaces(-118.291994, 36.578581, -116.83171, 36.23998)); // = 136 km
我正在使用简化的公式:
// cos(d) = sin(φА)·sin(φB) + cos(φА)·cos(φB)·cos(λА − λB),
// where φА, φB are latitudes and λА, λB are longitudes
// Distance = d * R
public static double DistanceBetweenPlaces(double lon1, double lat1, double lon2, double lat2)
{
double R = 6371; // km
double sLat1 = Math.Sin(Radians(lat1));
double sLat2 = Math.Sin(Radians(lat2));
double cLat1 = Math.Cos(Radians(lat1));
double cLat2 = Math.Cos(Radians(lat2));
double cLon = Math.Cos(Radians(lon1) - Radians(lon2));
double cosD = sLat1*sLat2 + cLat1*cLat2*cLon;
double d = Math.Acos(cosD);
double dist = R * d;
return dist;
}
Testing:
(赤道距离):经度 0、100;纬度 = 0,0;地点之间的距离(0, 0, 100, 0) = 11119.5 公里
(北极距离):经度 0、100;纬度 = 90,90;地点之间的距离(0, 90, 100, 90) = 0 公里
经度:-118.291994、-116.83171;纬度:36.578581, 36.23998 = 135.6 公里
经度:36.578581、36.23998;纬度:-118.291994,-116.83171 = 163.2 公里
此致
P.S. At web site http://www.movable-type.co.uk/scripts/latlong.html您用于结果比较,对于每个点,第一个文本框是纬度,第二个文本框是经度