我正在尝试制作一个控制台聊天程序,但我的循环有问题。我无法同时获得输入和接收其他人的输入。如果一端发送了两条或更多消息,则另一端在发送一条消息之前无法接收下一条消息。我对 python 相当陌生,正在寻找正确方向的推动。我考虑过多线程,但这有点超出我的理解范围。还有其他想法吗?
import EncMod
from socket import *
#Get User Info
Ip = raw_input('IP>>>')
Port = int(raw_input('Port>>>'))
User = raw_input('Username>>>')
#Open Socket To Server
EncCon = socket(AF_INET, SOCK_STREAM)
EncCon.connect((Ip, Port))
print '\nStarting Chat....'
print '\n<-------------------------------------------->\n\n'
#Send/Receive Loop
while 1:
MsgOut = raw_input()
if MsgOut: EncCon.send(MsgOut)
MsgIn = EncCon.recv(1024)
if MsgIn: print MsgIn
EncCon.close()
The 扭曲的框架 http://twistedmatrix.com/trac/可以用来帮助完成这项任务。下面的代码启动一个聊天服务器,然后客户端可以根据服务器实例设置连接到该服务器并进行来回通信。您可以进行适当的修改以满足您的要求:
from twisted.internet.protocol import Factory
from twisted.protocols.basic import LineReceiver
from twisted.internet import reactor
class Chat(LineReceiver):
def __init__(self, users):
self.users = users
self.name = None
self.state = "GETNAME"
def connectionMade(self):
self.sendLine("What's your name?")
def connectionLost(self, reason):
if self.users.has_key(self.name):
del self.users[self.name]
def lineReceived(self, line):
if self.state == "GETNAME":
self.handle_GETNAME(line)
else:
self.handle_CHAT(line)
def handle_GETNAME(self, name):
if self.users.has_key(name):
self.sendLine("Name taken, please choose another.")
return
self.sendLine("Welcome, %s!" % (name,))
self.name = name
self.users[name] = self
self.state = "CHAT"
def handle_CHAT(self, message):
message = "<%s> %s" % (self.name, message)
for name, protocol in self.users.iteritems():
if ':' in message:
self.exc(message.split(':')[0])
if protocol != self:
protocol.sendLine(message)
def exc(self, cmd):
print cmd
if cmd == 'who':
for i in self.users:
print i
class ChatFactory(Factory):
def __init__(self):
self.users = {} # maps user names to Chat instances
def buildProtocol(self, addr):
return Chat(self.users)
reactor.listenTCP(8123, ChatFactory())
reactor.run()
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