SQL 语法错误 - 半正矢公式

我试图获取最近的地点 https://stackoverflow.com/questions/4645490/get-nearest-places-google-maps-mysql-spatial-data/4979891使用 WordPress 数据库半正矢公式 http://en.wikipedia.org/wiki/Haversine_formula

我的表结构如下

posts

+--------------+
| Field        |
+--------------+
| ID           |
| post_author  |
| post_title   | 
| post_type    | 
+--------------+

postmeta

+--------------+
| Field        |
+--------------+
| meta_id      |
| post_id      |
| meta_key     |
| meta_value   |
+--------------+

并有记录meta_key values latitude and longitude

See the 回答我之前的问题 https://stackoverflow.com/questions/13249724/selecting-a-join-tables-column-values-as-result-column-name对于我用来获取纬度和经度的 SQL。

SELECT p.ID, 
  p.post_title, 
  p.post_author,
  max(case when pm.meta_key='latitude' then pm.meta_value end) latitude,
  max(case when pm.meta_key='longitude' then pm.meta_value end) longitude
FROM `wp_posts` p
LEFT JOIN `wp_postmeta` pm
  on p.ID=pm.post_id 
WHERE p.post_type='place' 
  AND (pm.meta_key='latitude' OR pm.meta_key='longitude') 
GROUP BY p.ID, p.post_title, p.post_author
ORDER BY p.ID ASC

现在我想将上面的查询合并到回答这个问题 https://stackoverflow.com/questions/4645490/get-nearest-places-google-maps-mysql-spatial-data/4979891#4979891

SELECT item1, item2, 
    ( 3959 * acos( cos( radians(37) ) 
                   * cos( radians( lat ) ) 
                   * cos( radians( lng ) 
                       - radians(-122) ) 
                   + sin( radians(37) ) 
                   * sin( radians( lat ) ) 
                 )
   ) AS distance 
FROM geocodeTable 
HAVING distance < 25 
ORDER BY distance LIMIT 0 , 20;

下面是组合查询

SELECT ID, 
  post_title, 
  post_author,
  max(case when meta_key='latitude' then meta_value end) latitude,
  max(case when meta_key='longitude' then meta_value end) longitude,
  ( 3959 * acos( cos( radians(18.204540500000) ) 
                   * cos( radians( latitude ) ) 
                   * cos( radians( longitude ) 
                       - radians(-66.450958500000) ) 
                   + sin( radians(18.204540500000 ) 
                   * sin( radians( latitude ) ) 
                 )
   ) AS distance 
FROM `wp_posts` 
LEFT JOIN `wp_postmeta` 
  on ID=post_id 
WHERE post_type='place' 
  AND (meta_key='latitude' OR meta_key='longitude') 
GROUP BY ID, post_title, post_author
ORDER BY ID ASC

但这会产生语法错误

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS distance FROM `wp_posts` LEFT JOIN `wp_postmeta` on ID=post_id WHERE po' at line 13

你错过了一个结束语)为了第一sin()

( 3959 * acos( cos( radians(18.204540500000) ) 
                   * cos( radians( latitude ) ) 
                   * cos( radians( longitude ) 
                       - radians(-66.450958500000) ) 
                   + sin( radians(18.204540500000 ) ) /* <--- here */
                   * sin( radians( latitude ) ) 
              )
 ) AS distance 

虽然很难从视觉上发现，但我通过将代码复制到支持大括号匹配的文本编辑器中发现了这一点。强烈建议使用一种，如果不是用于查询开发和测试，那么至少用于调试。