保留 Rxjs 生成的复选框的状态

基于在下拉列表中选择不同的项目，我生成带有复选框的项目的 html。如何保留复选框的状态，即每当下拉列表中的值发生变化时选中/取消选中。请参阅此处的 plunkrhttps://plnkr.co/edit/PUG3g7dfTbQjPyIgGLzh?p=preview https://plnkr.co/edit/PUG3g7dfTbQjPyIgGLzh?p=preview

Steps:

- uncheck 'abc2'
- change dd value to 'international'
- again change the dd value to 'local'
- here 'abc2' must be unchecked...

这是我的代码：

var data = [
    {type: 'local', name: 'abc1', location: 'xyz1', checked: true},
    {type: 'local', name: 'abc2', location: 'xyz2', checked: true},
    {type: 'international', name: 'abc3', location: 'xyz3', checked: true},
    {type: 'local', name: 'abc4', location: 'xyz4', checked: true},
    {type: 'local', name: 'abc5', location: 'xyz5', checked: true},
    {type: 'international', name: 'abc6', location: 'xyz6', checked: true},
    {type: 'international', name: 'abc7', location: 'xyz7', checked: true}
];

var $container = $('#container');
var $splitDD = $('#testDD');
var splitDD$ = Rx.Observable.fromEvent($splitDD, 'change')
    .startWith($splitDD.val())
    .map(function(e) { $container.html(''); return e.target ? e.target.value : e;})
    .switchMap(function(v) {return data;})
    .filter(function(v) {
      return v.type == $splitDD.val()
    })
    .map(getHtml)
    .subscribe(function(html) {
            $container.append(html);
    });


function getHtml(v) {
    var checked = v.checked ? 'checked="checked"' : '';
    var html = '<label><input class="point" name="' + v.name + '" type="checkbox" ' + checked + '>' +
        '<span>' + v.name + ' </span>' +
        '</label>';
    return html;
}

这里就解决了：https://plnkr.co/edit/72ciT20saCpLCLFNBbGv?p=preview https://plnkr.co/edit/72ciT20saCpLCLFNBbGv?p=preview

Steps:

added onclick监听复选框，当复选框更改时，数组正在更新。

1) in getHTML()

var html = '<label><input onclick="CheckboxPreserve(this);"   ......

2）在scripts.js底部添加：

function CheckboxPreserve(el){
  var $this = $(el);
  for (var key in data) {
      if (data[key]['name']==$this.attr("name")) {
          data[key]['checked']=$this.is(':checked');
      } 
  }
}