时差节目

我正在使用以下函数来计算时差。它没有显示正确的输出。 1 个月的时差后显示 2 分钟的差异。

我的程序出了什么问题？

public String TimestampDiff(Timestamp t) {
    long t1 = t.getTime();
    String st = null;
    long diff;
    java.util.Date date = new java.util.Date();
    long currT = date.getTime();
    System.out.println();
    System.out.println(" current timesstamp is  " + currT);

    diff = (currT - t1) / 60;
    int years = (int) Math.floor(diff / (1000 * 60 * 60 * 24 * 365));
    double remainder = Math.floor(diff % (1000 * 60 * 60 * 24 * 365));
    int days = (int) Math.floor(remainder / (1000 * 60 * 60 * 24));
    remainder = Math.floor(remainder % (1000 * 60 * 60 * 24));
    int hours = (int) Math.floor(remainder / (1000 * 60 * 60));
    remainder = Math.floor(remainder % (1000 * 60 * 60));
    int minutes = (int) Math.floor(remainder / (1000 * 60));
    remainder = Math.floor(remainder % (1000 * 60));
    int seconds = (int) Math.floor(remainder / (1000));
    System.out.println("\nyr:Ds:hh:mm:ss " + years + ":" + days + ":"
            + hours + ":" + minutes + ":" + seconds);

    if (years == 0 && days == 0 && hours == 0 && minutes == 0) {
        st = "few seconds ago";
    } else if (years == 0 && days == 0 && hours == 0) {
        st = minutes + " minuts ago";
    } else if (years == 0 && days == 0) {
        st = hours + " hours ago";
    } else if (years == 0 && days == 1) {
        st = new SimpleDateFormat("'yesterday at' hh:mm a").format(t1);

    } else if (years == 0 && days > 1) {
        st = new SimpleDateFormat(" MMM d 'at' hh:mm a").format(t1);

    } else if (years > 0) {
        st = new SimpleDateFormat("MMM d ''yy 'at' hh:mm a").format(t1);

    }
    st = st.replace("AM", "am").replace("PM", "pm");
    return st;
}

我建议看一下乔达时间 http://www.joda.org/joda-time/，注意到：

Joda-Time 是 Java SE 8 之前的 Java 事实上的标准日期和时间库。现在要求用户迁移到 java.time (JSR-310)。

安装

• 对于基于 Debian 的系统：libjoda-time-java。罐子将在/usr/share/java as joda-time.jar
• 为他人：Download https://sourceforge.net/projects/joda-time/files/joda-time/最新的罐子，例如joda-time-2.2-dist.zip 其中包括 joda-time-2.2.jar

使用 Eclipse 时，将其添加到 Java 构建路径（项目 > 属性 > Java 构建路径 > 添加外部 Jar）

相关Java文档

• DateTime http://joda-time.sourceforge.net/apidocs/org/joda/time/DateTime.html
• Period http://joda-time.sourceforge.net/apidocs/org/joda/time/Period.html
• 周期格式化程序 http://joda-time.sourceforge.net/apidocs/org/joda/time/format/PeriodFormatter.html
• 周期格式化程序生成器 http://joda-time.sourceforge.net/apidocs/org/joda/time/format/PeriodFormatterBuilder.html

示例代码

import java.sql.Timestamp;
import java.util.Date;
import org.joda.time.DateTime;
import org.joda.time.Period;
import org.joda.time.format.PeriodFormatter;
import org.joda.time.format.PeriodFormatterBuilder;

public class MinimalWorkingExample {
    static Date date = new Date(1990, 4, 28, 12, 59);

    public static String getTimestampDiff(Timestamp t) {
        final DateTime start = new DateTime(date.getTime());
        final DateTime end = new DateTime(t);
        Period p = new Period(start, end);
        PeriodFormatter formatter = new PeriodFormatterBuilder()
                .printZeroAlways().minimumPrintedDigits(2).appendYears()
                .appendSuffix(" year", " years").appendSeparator(", ")
                .appendMonths().appendSuffix(" month", " months")
                .appendSeparator(", ").appendDays()
                .appendSuffix(" day", " days").appendSeparator(" and ")
                .appendHours().appendLiteral(":").appendMinutes()
                .appendLiteral(":").appendSeconds().toFormatter();
        return p.toString(formatter);
    }

    public static void main(String[] args) {
        String diff = getTimestampDiff(new Timestamp(2013, 3, 20, 7, 51, 0, 0));
        System.out.println(diff);
    }
}

Output:

22 years, 10 months, 01 day and 18:52:00

为什么我推荐新的解决方案

• 它更短（726 个字符/14 行，而您的 1665 个字符/41 行）
• 更容易理解
• 调整起来比较容易
• 代码和表示的分离更加清晰
• 我不想修复你的代码