我在更改 Matplotlib 中的轴标签时遇到问题。我想更改极坐标图中的径向轴选项。
基本上,我正在计算圆柱体的变形,这只不过是半径偏离原始(完美圆形)圆柱体的程度。由于拉力和压力,一些变形值为负值,而另一些则为正值。我正在寻找一种方法以图形方式在柱坐标中表示这一点,所以我认为极坐标图是我最好的选择。 Excel 为我提供了一个“雷达图”选项,该选项足够灵活,可以让我指定最小和最大径向轴值。我想使用 Matplotlib 在 Python 上复制这个。
我用于在极坐标上绘图的 Python 脚本如下。
#!usr/bin/env python
import matplotlib.pyplot as plt
import numpy as np
x = np.arange(-180.0,190.0,10)
theta = (np.pi/180.0 )*x # in radians
offset = 2.0
R1 = [-0.358,-0.483,-0.479,-0.346,-0.121,0.137,0.358,0.483,0.479,0.346,0.121,\
-0.137,-0.358,-0.483,-0.479,-0.346,-0.121,0.137,0.358,0.483,0.479,0.346,0.121,\
-0.137,-0.358,-0.483,-0.479,-0.346,-0.121,0.137,0.358,0.483,0.479,0.346,0.121,\
-0.137,-0.358]
fig1 = plt.figure()
ax1 = fig1.add_axes([0.1,0.1,0.8,0.8],polar=True)
ax1.set_rmax(1)
ax1.plot(theta,R1,lw=2.5)
My plot looks as follows:
But this is not how I want to present it. I want to vary my radial axis, so that I can show the data as a deviation from some reference value, say -2. How do I ask Matplotlib in polar coordinates to change the minimum axis label? I can do this VERY easily in Excel. I choose a minimum radial value of -2, to get the following Excel radar chart:
在 Python 上,我可以轻松地将输入数据偏移 2 个量级。我的新数据集称为 R2,如下所示:
#!usr/bin/env python
import matplotlib.pyplot as plt
import numpy as np
x = np.arange(-180.0,190.0,10)
theta = (np.pi/180.0 )*x # in radians
offset = 2.0
R2 = [1.642,1.517,1.521,1.654,1.879,2.137,2.358,2.483,2.479,2.346,2.121,1.863,\
1.642,1.517,1.521,1.654,1.879,2.137,2.358,2.483,2.479,2.346,2.121,1.863,1.642,\
1.517,1.521,1.654,1.879,2.137,2.358,2.483,2.479,2.346,2.121,1.863,1.642]
fig2 = plt.figure()
ax2 = fig2.add_axes([0.1,0.1,0.8,0.8],polar=True)
ax2.plot(theta,R2,lw=2.5)
ax2.set_rmax(1.5*offset)
plt.show()
The plot is shown below:
一旦我得到这个,我可以手动添加轴标签并将其硬编码到我的脚本中。但这是一种非常丑陋的方式。有什么方法可以直接获得与 Excel 雷达图等效的 Matplotlib 并更改我的轴标签,而无需操作我的输入数据?