你好 TypeScript 专家。
我有以下代码，但我必须在类中重复接口属性，否则我会得到：
类错误地实现了接口
使用接口时，是否有 TypeScript 简写可以执行此操作而无需声明Id: number;以及该类中的所有其他属性？谢谢
interface INavigation {
Id: number;
AppId: number;
NavId: number;
Name: string;
ParentId: string;
PageURL: string;
Position: string;
Active: string;
Desktop: string;
Tablet: string;
Phone: string;
RoleId: string;
Target: string;
}
class Navigation implements INavigation {
Id: number;
AppId: number;
NavId: number;
Name: string;
ParentId: string;
PageURL: string;
Position: string;
Active: string;
Desktop: string;
Tablet: string;
Phone: string;
RoleId: string;
Target: string;
constructor(navigation: any) {
this.Id = navigation.Id
this.AppId = navigation.NavAppId
this.NavId = navigation.NavId
this.Name = navigation.NavName
this.ParentId = navigation.NavParentId
this.PageURL = navigation.NavPageURL
this.Position = navigation.NavPosition
this.Active = navigation.NavActive
this.Desktop = navigation.NavDesktop
this.Tablet = navigation.NavTablet
this.Phone = navigation.NavPhone
this.RoleId = navigation.NavRoleId
this.Target = navigation.NavTarget
}
}
现在可以在 Typescript 中使用类/接口合并来实现这一点。
interface Foo {
a: number;
}
interface Baz extends Foo { }
class Baz {
constructor() {
console.log(this.a); // no error here
}
}
https://github.com/Microsoft/TypeScript/issues/340#issuecomment-184964440 https://github.com/Microsoft/TypeScript/issues/340#issuecomment-184964440
本文内容由网友自发贡献，版权归原作者所有，本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容，请联系:hwhale#tublm.com(使用前将#替换为@)
