我正在尝试使用以下代码将我的 AS400 与 V5R3 和 PHP 连接:
<?php
$server="Driver={Client Access ODBC Driver (32-bit)};System=xxx.xxx.xxx.xxx;
Uid=user;Pwd=password;"; #the name of the iSeries
$user="user"; #a valid username that will connect to the DB
$pass="password"; #a password for the username
$conn=odbc_connect($server,$user,$pass); #you may have to remove quotes
#Check Connection
if ($conn == false) {
echo "Not able to connect to database...<br>";
}
#Query the Database into a result set -
$result=odbc_exec($conn,"SELECT * FROM LIBRARY.V5TDOC0L WHERE T§DTDO = 20120319");
if (!$result)
{exit("Error in SQL");}
echo "<table><tr>";
echo "<th>T§NDOC</th>";
echo "<th>T§DTDO</th></tr>";
while (odbc_fetch_row($result))
{
$ndoc=odbc_result($result,2);
$dtdo=odbc_result($result,3);
echo "<tr><td>$ndoc</td>";
echo "<td>$dtdo</td></tr>";
}
echo "</table>";
#close the connection
odbc_close($conn);
?>
我收到这个错误:
警告:odbc_exec() [function.odbc-exec]:SQL 错误:[IBM][System i Access 的 ODBC 控制程序][DB2 per i5/OS]SQL0104 - 令牌无效。令牌有效: = != >= � �= IN IS NOT LIKE BETWEEN., SQLExecDirect 中的 SQL 状态 37000 F:\xampp\htdocs\php-as400\php- as400.php 第 25 行
SQL 错误
从语句 SELECT 中删除WHERE T§DTDO = 20120319
,我让它运行并列出我想要的元素并发出警告。
Fatal error: Maximum execution time of 30 seconds exceeded in F:\xampp\htdocs\php-as400\php-as400.php on line 30
T§NDOC T§DTDO
C008931 19941102
P005027 19950214
P005031 19950320
P005055 19950612
P005062 19950904
P005065 19950920
P005082 19951218
P005157 19970102
P005186 19970428
P005187 19970429
P005190 19970520
I009353 19970721
P005257 19980217
第 30 行是:
while (odbc_fetch_row($result))
我相信问题出在性格§上,正如我在互联网上发现的那样(https://bugs.php.net/bug.php?id=47133 https://bugs.php.net/bug.php?id=47133),但我不知道如何解决。