我正在尝试在前面创建一个“编辑个人资料”表单。发生的情况是我的表单(我不是 100% 确定)尝试创建一个用户,而不是查找当前用户并更新他的个人资料。所以我认为这就是问题所在。在这里检查了很多问题,但没有一个足够清楚。我尝试编辑的字段是电子邮件、名字和姓氏。 (我还想添加 uda
forms.py
class UpdateProfile(forms.ModelForm):
username = forms.CharField(required=True)
email = forms.EmailField(required=True)
first_name = forms.CharField(required=False)
last_name = forms.CharField(required=False)
class Meta:
model = User
fields = ('username', 'email', 'first_name', 'last_name')
def clean_email(self):
username = self.cleaned_data.get('username')
email = self.cleaned_data.get('email')
if email and User.objects.filter(email=email).exclude(username=username).count():
raise forms.ValidationError('This email address is already in use. Please supply a different email address.')
return email
def save(self, commit=True):
user = super(RegistrationForm, self).save(commit=False)
user.email = self.cleaned_data['email']
if commit:
user.save()
return user
views.py
def update_profile(request):
args = {}
if request.method == 'POST':
form = UpdateProfile(request.POST)
form.actual_user = request.user
if form.is_valid():
form.save()
return HttpResponseRedirect(reverse('update_profile_success'))
else:
form = UpdateProfile()
args['form'] = form
return render(request, 'registration/update_profile.html', args)
你们非常接近。当你实例化表单时,你需要传递User
您正在修改的对象instance
争论。
来自文档:
ModelForm 的子类可以接受现有的模型实例作为
关键字参数instance
;如果提供, save() 将更新
那个例子。
在您的代码中,它看起来像:
form = UpdateProfile(request.POST, instance=request.user)
if form.is_valid():
...
您可以在此处查看更多信息:https://docs.djangoproject.com/en/1.6/topics/forms/modelforms/#the-save-method https://docs.djangoproject.com/en/1.6/topics/forms/modelforms/#the-save-method
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