Ruby：转换数组中的对象后传递键/值

给定数据：

data = [
 {"id":14, "sort":1, "content":"9", foo: "2022"},
 {"id":14, "sort":4, "content":"5", foo: "2022"},
 {"id":14, "sort":2, "content":"1", foo: "2022"},
 {"id":14, "sort":3, "content":"0", foo: "2022"},
 {"id":15, "sort":4, "content":"4", foo: "2888"},
 {"id":15, "sort":2, "content":"1", foo: "2888"},
 {"id":15, "sort":1, "content":"3", foo: "2888"},
 {"id":15, "sort":3, "content":"3", foo: "2888"},
 {"id":16, "sort":1, "content":"8", foo: "3112"},
 {"id":16, "sort":3, "content":"4", foo: "3112"},
 {"id":16, "sort":2, "content":"4", foo: "3112"},
 {"id":16, "sort":4, "content":"9", foo: "3112"}
]

得到了他们连接的内容sort and ids with:

formatted = data.group_by { |d| d[:id]}.transform_values do |value_array|
  value_array.sort_by { |b| b[:sort] }
             .map     { |c| c[:content] }.join
end

puts formatted
#=> {14=>"9105", 15=>"3134", 16=>"8449"}

我知道foo存在于里面value_array但想知道我怎样才能包括foo存在于formatted变量，以便我可以映射它以获得所需的输出，或者是否可能？

期望的输出：

[
 {"id":14, "concated_value":"9105", foo: "2022"},
 {"id":15, "concated_value":"3134", foo: "2888"},
 {"id":16, "concated_value":"8449", foo: "3112"}
]

Since :foo是独一无二的:id。您可以按如下方式执行此操作：

data.group_by {|h| h[:id]}.map do |_,sa| 
  sa.map(&:dup).sort_by {|h| h.delete(:sort) }.reduce do |m,h| 
     m.merge(h) {|key,old,new| key == :content ? old + new : old } 
  end.tap {|h| h[:concated_value] = h.delete(:content) }
end  
#=> [
# {"id":14, foo: "2022", "concated_value":"9105"},
# {"id":15, foo: "2888", "concated_value":"3134"},
# {"id":16, foo: "3112", "concated_value":"8449"}
# ]

• 首先我们按 id 分组。group_by {|h| h[:id]}
• 然后我们复制组中的哈希值（以免破坏原始哈希值）。map(&:dup)
• 然后我们按so​​rt排序，同时删除。.sort_by {|h| h.delete(:sort) }
• 然后我们将组合并在一起并仅连接内容键。m.merge(h) {|key,old,new| key == :content ? old + new : old }
• 然后我们只需更改密钥content to concated_value tap {|h| h[:concated_value] = h.delete(:content) }