如何选择特定客户？

我创建了以下表格：

create table customers (
        ID      varchar(9),
        name    varchar(15), 
        CONSTRAINT pk_id PRIMARY KEY (ID)
);

create table living_places (
        code    varchar(7),
        ID      varchar(9),
        CONSTRAINT pk_code PRIMARY KEY (code)
);

create table policies (
        code_policy         varchar(7),
        code_living_place   varchar(7),
        CONSTRAINT pk_code_policy PRIMARY KEY (code_policy)
);

create table bills (
        code          varchar(7),
        code_policy   varchar(7),
        paid_out      boolean,
        CONSTRAINT pk_code_bill PRIMARY KEY (code)
);

我插入了以下日期：

insert into customers(ID, name) values('fx1','Louis');
insert into customers(ID, name) values('fx2','Peter');
insert into customers(ID, name) values('fx3','Alice');

insert into living_places(code, ID) values('001','fx1');
insert into living_places(code, ID) values('002','fx2');
insert into living_places(code, ID) values('003','fx1');
insert into living_places(code, ID) values('004','fx3');

insert into policies(code_policy, code_living_place) values('p1','001');
insert into policies(code_policy, code_living_place) values('p2','002');
insert into policies(code_policy, code_living_place) values('p3','003');

insert into bills(code, code_policy, paid_out) values('b1','p1','1');
insert into bills(code, code_policy, paid_out) values('b2','p1','1');
insert into bills(code, code_policy, paid_out) values('b3','p2','0');
insert into bills(code, code_policy, paid_out) values('b4','p2','1');
insert into bills(code, code_policy, paid_out) values('b5','p3','0');
insert into bills(code, code_policy, paid_out) values('b6','p3','1');

问题是：如何选择那些已支付所有保单的人？

我的问题是Louis有两项政策p1 and p3。政策p1已付款但p3 is not.

我的查询：

select ID from living_places where code in (
select code from living_places where code in (
select code_living_place from policies where code_policy in (
select code_policy from bills where paid_out=1 and code_policy not in (
select code_policy from bills where paid_out=0))));

MySQL 返回给我：

+------+
| ID   |
+------+
| fx1  |
+------+

P.S: Louis没有支付所有保单。例如，账单b5未付款。

很确定是这样的：

select c.ID, c.name
from customers c
where c.ID in (
    select lp.id
    from policies p
    join living_places lp on p.code_living_place = lp.code
    join bills b on b.code_policy = p.code_policy
    group by lp.id
    having sum(b.paid_out = 1) = count(*));

它会返回 0 条记录，其中包含您当前拥有的数据，如果您将 Louis 尚未支付的一张账单修改为已支付，那么他将显示在结果中。

这是一个可以使用的 SQL Fiddle。 http://sqlfiddle.com/#!9/b641f/49