我有一个自定义模板标签：
def uploads_for_user(user):
uploads = Uploads.objects.filter(uploaded_by=user, problem_upload=False)
num_uploads = uploads.count()
return num_uploads
我想做这样的事情，这样我就可以正确地复数：
{% with uploads_for_user leader as upload_count %}
{{ upload_count }} upload{{ upload_count|pluralize }}
{% endwith %}
然而，uploads_for_user leader在这种情况下不起作用，因为“with”标签需要单个值 - Django 返回：
TemplateSyntaxError at /upload/
u'with' expected format is 'value as name'
知道我该如何解决这个问题吗？
你可以把它变成一个过滤器：
{% with user|uploads_for as upload_count %}
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