如果我从终端运行此请求,我可以正常看到 JSON 请求:
curl -XGET 192.168.0.6:8888/scripts/data/backend2/index.php/name/_all
我的 NSURlRequest 代码是这样的:
NSURLRequest *request = [NSURLRequest requestWithURL:
[NSURL URLWithString:@"192.168.0.6:8888/scripts/data/backend2/index.php/name/_all"]];
[[NSURLConnection alloc] initWithRequest:request delegate:self];
我收到此错误:
didFailWithError
2013-11-29 22:31:08.164 Ski Greece[607:a0b] Connection failed: Error Domain=NSURLErrorDomain Code=-1002 "unsupported URL" UserInfo=0xcd042d0 {NSErrorFailingURLStringKey=192.168.0.6:8888/scripts/data/backend2/index.php/name/_all, NSErrorFailingURLKey=192.168.0.6:8888/scripts/data/backend2/index.php/name/_all, NSLocalizedDescription=unsupported URL, NSUnderlyingError=0xdbdcc70 "unsupported URL"}
我怎样才能调用该 URL?我无法访问服务器代码 - 我知道它只是设置为返回我需要的内容,如果我调用该 URL?
尝试在您的网址中包含适当的网址方案,例如
[NSURL URLWithString:@"http://www...
本文内容由网友自发贡献,版权归原作者所有,本站不承担相应法律责任。如您发现有涉嫌抄袭侵权的内容,请联系:hwhale#tublm.com(使用前将#替换为@)