我想做一个纸牌游戏。我所坚持的是发牌。我所做的就是对每张卡制定一个指令，并赋予它一个值，因为有些卡比其他卡更有价值。我的想法是将字典分成4部分，或者将每本字典复印4份，然后从每份中删除39张卡片（每人留下13张卡片）。这是否可能，或者我是否以错误的方式处理这个问题？
from random import randint
deck = {}
def makeDeck(deck):
suit = ['Club', 'Spade', 'Heart', 'Diamond']
whichSuit = 0
whichNum = 2
count = 1
while count != 52:
if whichNum == 11:
whichNum = 'Jack'
if whichNum == 12:
whichNum = 'Queen'
if whichNum == 13:
whichNum = 'King'
if whichNum == 14:
whichNum = 'Ace'
deck[str(whichNum)+' '+suit[whichSuit]] = count
count += 1
if whichNum == 'Jack':
whichNum = 11
if whichNum == 'Queen':
whichNum = 12
if whichNum == 'King':
whichNum = 13
if whichNum == 'Ace':
whichNum = 14
whichNum += 1
if count == 13 or count == 26 or count == 39:
whichSuit += 1
whichNum = 2
def dealCards(deck):
me = deck
comp1 = deck
comp2 = deck
comp2 = deck
（抱歉，如果代码有误，这是我的第一篇文章，谢谢）
听起来是一个使用课程的好机会！我会这样做：
from random import shuffle
class Cards:
def __init__(self):
values = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K']
suites = ['H', 'S', 'C', 'D']
self.deck = [j + i for j in values for i in suites]
def shuffle(self):
shuffle(self.deck)
def deal(self, n_players):
self.hands = [self.deck[i::n_players] for i in range(0, n_players)]
c = Cards()
print c.deck
c.shuffle()
print c.deck
c.deal(4)
print c.hands
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