打印出指定宽度的 ASCII 圆

我正在尝试更改以下代码，以便得到半径 2 的输出：

  *****
***   ***
**     **
***   ***
  *****

任何帮助将不胜感激，因为我快要疯了！

public class Main {
    public static void main(String[] args) {
        // dist represents distance to the center
        double dist;
        double radius = 2;

        // for horizontal movement
        for (int i = 0; i <= 2 * radius; i++) {
            // for vertical movement
            for (int j = 0; j <= 2 * radius; j++) {
                dist = Math.sqrt(
                        (i - radius) * (i - radius) +
                        (j - radius) * (j - radius));

                // dist should be in the range (radius - 0.5)
                // and (radius + 0.5) to print stars(*)
                if (dist > radius - 0.5 && dist < radius + 0.5)
                    System.out.print("*");
                else
                    System.out.print(" ");
            }
            System.out.println("");
        }
    }
}

输出看起来是椭圆形的，因为字符的宽度和高度不同。想象一个图像，它的像素不是正方形，而是垂直的矩形。我借了c# /questions/tagged/c%23@Prasanth Rajendran 链接的代码版本，并做了一些修改：

1. added lineWidth争论
2. added xScale争论，现在每个1/xScale一行中的字符相当于1数据点
3. 通过添加 [0.5, 0.5] 偏移量将字符位置移动到其中心

// function to print circle pattern 
static void printPattern(int radius, int lineWidth, double xScale)
{
    double hUnitsPerChar = 1 / xScale;
    double hChars = (2 * radius + lineWidth) / hUnitsPerChar;
    double vChars = 2 * radius + lineWidth;
    // dist represents distance to the center 
    double dist;
    double lineWidth_2 = (double)lineWidth / 2;
    double center = radius + lineWidth_2;
    // for vertical movement 
    for (int j = 0; j <= vChars - 1; j++)
    {
        double y = j + 0.5;
        // for horizontal movement 
        for (int i = 0; i <= hChars - 1; i++)
        {
            double x = (i + 0.5) * hUnitsPerChar;
            dist = Math.Sqrt(
                (x - center) * (x - center) +
                (y - center) * (y - center));

            // dist should be in the range  
            // (radius - lineWidth/2) and (radius + lineWidth/2)  
            // to print stars(*) 
            if (dist > radius - lineWidth_2 &&
                            dist < radius + lineWidth_2)
                Console.Write("*");
            else
                Console.Write(" ");
        }

        Console.WriteLine("");
    }
}
static void Main(string[] args)
{
    printPattern(2, 1, 2);
    printPattern(10, 3, 2);
}

现在结果是这样的：

printPattern(2, 1, 2):

  ******
***    ***
**      **
***    ***
  ******

printPattern(10, 3, 2):

                **************
            **********************
         ****************************
      ***********            ***********
     ********                    ********
   ********                        ********
  *******                            *******
 *******                              *******
 ******                                ******
******                                  ******
******                                  ******
******                                  ******
******                                  ******
******                                  ******
 ******                                ******
 *******                              *******
  *******                            *******
   ********                        ********
     ********                    ********
      ***********            ***********
         ****************************
            **********************
                **************

它们在 CMD 中看起来更好：

希望你能把它翻译成java /questions/tagged/java.