在 Python 中将 2D 图形转换为圆柱体

At the moment I have a figure that looks like this,

由代码生成：

import matplotlib.pyplot as plt

import numpy as np

data = np.random.rand(20,5)
rows,cols = data.shape

plt.imshow(data, interpolation='nearest', extent=[0.5, 0.5+cols, 0.5,   0.5+cols], cmap='bwr')
plt.show()

不过，我想将其“折叠”成 3D 圆柱体，连接左右边缘（就像处理一张纸一样）。换句话说，左边缘和右边缘实际上是同一条边缘，所以我想将它们连接在一起形成一个圆柱体。

我该怎么做呢？

The Poly3DCollection是任意 3D 多边形的选择方法mplot3d.

from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
import numpy as np

fig = plt.figure()
ax = fig.gca(projection='3d')

nphi,nz=12,20
r=1 # radius of cylinder
phi = np.linspace(0,360, nphi)/180.0*np.pi
z= np.linspace(0,1.0,nz)
print z

facecolors=['r','g','b','y']
cols=[]
verts2 = []
for i  in range(len(phi)-1):
    cp0= r*np.cos(phi[i])
    cp1= r*np.cos(phi[i+1])
    sp0= r*np.sin(phi[i])
    sp1= r*np.sin(phi[i+1])

    for j in range(len(z)-1):
        z0=z[j]
        z1=z[j+1]
        verts=[]
        verts.append((cp0, sp0, z0))
        verts.append((cp1, sp1, z0))
        verts.append((cp1, sp1, z1))
        verts.append((cp0, sp0, z1))
        verts2.append(verts)
        value=np.random.rand()
        print value
        col=plt.cm.bwr(value)
        print col
        cols.append(col)

poly3= Poly3DCollection(verts2, facecolor=cols  )  

poly3.set_alpha(0.8)
ax.add_collection3d(poly3)
ax.set_xlabel('X')
ax.set_xlim3d(-1, 1)
ax.set_ylabel('Y')
ax.set_ylim3d(-1, 1)
ax.set_zlabel('Z')
ax.set_zlim3d(0, 1)
plt.show()