tl;dr
由于您的目录名称包含spaces， 你必须quote它，例如：
# Note: In PowerShell, 'cd' is an alias of 'Set-Location'
cd 'Program Files'
Alternatively, if the intent is to change to the well-known programs folder (typically,
C:\Program Files), you may reference the relevant environment variable https://learn.microsoft.com/en-us/powershell/module/microsoft.powershell.core/about/about_Environment_Variables, in which case quoting is not required:[1]
cd $env:ProgramFiles instead of cd 'C:\Program Files'
下面讨论如何传递字符串literals以空格作为单个参数。
如中所述Maximilian Burszley 的有用回答 https://stackoverflow.com/a/51459512/45375, Program Files被解析为two参数，因为空格用于separate命令行参数。
Your attempt to use cd Program Files may be inspired by cmd.exe (the legacy Command Prompt), where this syntax indeed works; however, even there it conceptually violates the usual rules of argument parsing.
所以，你需要使用一种形式quoting为了传递一个值包含空格 as a single争论.
您有多种选择来实现此引用：
-
Use '...' around值是literals，即应该使用verbatim; a '...'字符串被称为verbatim（单引号）字符串 https://learn.microsoft.com/en-us/powershell/module/microsoft.powershell.core/about/about_Quoting_Rules#single-quoted-strings.
-
Use "..." around您想要嵌入的值变量引用 (e.g., $HOME) or 子表达式 (e.g., $(Get-Date);那是，"..."弦乐演奏字符串插值，他们被称为可扩展的（双引号）字符串 https://learn.microsoft.com/en-us/powershell/module/microsoft.powershell.core/about/about_Quoting_Rules#double-quoted-strings.
-
Use `引用（转义）asingle特点;`， 所谓的backtick, 是PowerShell的通用转义字符 https://learn.microsoft.com/en-us/powershell/module/microsoft.powershell.core/about/about_Special_Characters.
因此，您可以使用以下任意一种：
cd 'Program Files'
cd "Program Files" # as there are no $-prefixed tokens, same as 'Program Files'
cd Program` Files # `-escape just the space char.
Also, 您可以使用制表符补全扩展（无空间）prefix包含空间的路径的完整形式隐式引用.
例如，如果您在C:\然后你输入：
cd Program<tab>
PowerShell 自动完成命令：
cd '.\Program Files\'
请注意如何Program Files（随着.\引用当前目录。和一个尾随的\指示目录。）是自动单引号.
Using 通配符表达式作为参数:
如前所述，在 PowerShell 中cd是一个内置别名Set-Location https://learn.microsoft.com/powershell/module/microsoft.powershell.management/set-location cmdlet.
路过一条路位置上 - e.g. Set-Location 'C:\Program Files' - 隐式地将其绑定到-Path范围;就是这样，相当于Set-Location -Path 'C:\Program Files'
-Path将其论证解释为通配符表达式 https://learn.microsoft.com/en-us/powershell/module/microsoft.powershell.core/about/about_Wildcards，这样你就可以做类似的事情Set-Location C:\Win*为了改变为C:\Windows（假设通配符表达式仅匹配one目录）。
棘手的是 - 与cmd.exe- 这不仅仅是* and ?在 PowerShell 通配符表达式中具有特殊含义，但是[ and ]以及（对于字符集和字符范围表达式，例如[abc] and [a-c]）， 以便Set-Location Foo[1] will not更改目录的工作字面上地 named Foo[1].
在这种情况下，您必须使用-LiteralPath范围 -
Set-Location -LiteralPath Foo[1]- 确保路径是解释的字面上地（逐字）.
[1] This even applies if you append a space-less literal, e.g. cd $env:ProgramFiles\Git; however, if the literal part contains spaces, quoting is again needed; while, e.g., cd $env:ProgramFiles\'Common Files' works, the preferable approach is to enclose the entire argument in "...": cd "$env:ProgramFiles\Common Files"
