我正在尝试对字符串进行 url 编码，但 NSURLConnection 由于“错误的 url”而失败。这是我的网址：
NSString *address = mp.streetAddress;
NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *cityState= mp.cityState;
NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", encodedAddress, encodedCityState];
NSURL *url = [NSURL URLWithString:fullAddressURL];
以下是 API 调用 URL 的示例：
以下是调用 API 以获取精确地址匹配“2114 Bigelow Ave”、“Seattle, WA”的示例：
http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<ZWSID>&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA
由于某种原因，此 URL 无法连接。有人可以帮我吗？
您必须先对 fullAddressURL 进行编码，然后再将其发送到NSURL而不是单独编码地址和城市状态。
NSString *address = @"2114 Bigelow Ave";
//NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *cityState= @"Seattle, WA";
// NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", address, cityState];
fullAddressURL = [fullAddressURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog(@"fullAddressURL: %@",fullAddressURL);
NSURL *url = [NSURL URLWithString:fullAddressURL];
我已经测试了上面的代码，它给了我与给定链接相同的输出http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<ZWSID>&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA
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