我假设您正在使用 SQL Server 2008 或更高版本,这是使dense_rank() https://learn.microsoft.com/en-us/sql/t-sql/functions/dense-rank-transact-sql?view=sql-server-2017功能工作。
下面的解决方案经历了评论中概述的几个步骤。一个问题是我改变了其中之一@ProductRecipe
记录来自(22, 130)
to (22, 468)
因为我相信它是预期的样本数据,因为Component1
所需输出包括PricingID
值 316323 和 316329。
Answer:
DECLARE @ProductRecipe TABLE (ProductRecipeID INT, ComponentProductID INT)
INSERT INTO @ProductRecipe (ProductRecipeID, ComponentProductID) VALUES (21, 130)
INSERT INTO @ProductRecipe (ProductRecipeID, ComponentProductID) VALUES (21, 468)
INSERT INTO @ProductRecipe (ProductRecipeID, ComponentProductID) VALUES (21, 500)
INSERT INTO @ProductRecipe (ProductRecipeID, ComponentProductID) VALUES (22, 468) --values were (22, 130) in question
INSERT INTO @ProductRecipe (ProductRecipeID, ComponentProductID) VALUES (22, 500)
INSERT INTO @ProductRecipe (ProductRecipeID, ComponentProductID) VALUES (23, 130)
INSERT INTO @ProductRecipe (ProductRecipeID, ComponentProductID) VALUES (23, 501)
DECLARE @ComponentPricing TABLE (PricingID INT, ProductID INT)
INSERT INTO @ComponentPricing (PricingID, ProductID)
VALUES (314023, 130)
, (313616, 130)
, (313071, 130)
, (312865, 130)
, (316323, 468)
, (316329, 468)
, (398864, 500)
; with base as
(
--Joining the two datasets together.
select pr.ProductRecipeID
, pr.ComponentProductID
, cp.PricingID
from @ProductRecipe as pr
left join @ComponentPricing as cp on pr.ComponentProductID = cp.ProductID
)
, pr_exclude as
(
--Identifying that ProductRecipeID 23 should be excluded because of the 501 NULL value
select distinct b.ProductRecipeID
from base as b
where b.PricingID is null
)
, final_base as
(
--Assigning Rank to each ComponentProductID
select b.ProductRecipeID
, b.ComponentProductID
, b.PricingID
, dense_rank() over (partition by b.ProductRecipeID order by b.ComponentProductID asc) as prod_rnk
from base as b
left join pr_exclude as p on b.ProductRecipeID = p.ProductRecipeID
where 1=1
and p.ProductRecipeID is null
)
--Joining it all together
select a.ProductRecipeID
, a.PricingID as Component1
, b.PricingID as Component2
, c.PricingID as Component3
, d.PricingID as Component4
, e.PricingID as Component5
from final_base as a
left join final_base as b on a.ProductRecipeID = b.ProductRecipeID and b.prod_rnk = 2
left join final_base as c on b.ProductRecipeID = c.ProductRecipeID and c.prod_rnk = 3
left join final_base as d on c.ProductRecipeID = d.ProductRecipeID and d.prod_rnk = 4
left join final_base as e on d.ProductRecipeID = e.ProductRecipeID and e.prod_rnk = 5
where a.prod_rnk = 1
order by 1, 2, 3, 4, 5, 6