我使用的文件有 15 行,每行 2 个字符,因此假设文件的大小约为 44 字节,但使用tellg 函数,大小显示为 58。此外,我累积了一个包含所有位置的数组代码正在识别一个换行符,它们都是连续的,因此证实了这个疑问。谢谢你!
//Tailfile - This program accepts a file and prints the last 10 lines.
//This function determines the number of lines and how to display it
int lineidentifier(fstream&tailfile,long& position)
{
tailfile.seekg(0,ios::end);//sets the read position at the end of file.
long n=0;//counter for the number of lines
long i=tailfile.tellg();//counter for the number of characters set to
//thenumber of bytes in the file and hence, the end.
char ch;//To hold and check the character.
while(n<10&&i>=0)//conditions are as long as the number of characters
//are not exhausted or the number of lines
{
tailfile.seekg(i, ios::beg);//sets the read position to the end of
//the file by using the number of characters and the file
//mode as the beginning.
cout<<"1. "<<i<<endl;//DEBUGGING EXTRA
tailfile.get(ch);//Reads the content at i
tailfile.clear();//clears the eof flag set by the first iteration
//because we reach the end of the file.
cout<<"2. "<<i<<endl;//DEBUGGING EXTRA
if(ch=='\n')//if the character received is the newline character
//leading to us regarding it as a line has been identified.
{
n++;//Increment n accordingly.
position=i;//The position is the byte i is at before the
//character was read, hence the position of the character.
cout<<position<<endl;//DEBUGGING EXTRA
cout<<ch<<endl;//DEBUGGING EXTRA
i--;
}
i--;
cout<<"4. "<<i<<endl;//DEBUGGING EXTRA
}
cout<<i<<endl;//DEBUGGING EXTRA
if(i<=1)//Using the position of i to indicate whether the file has more
//than 10 lines. If i is less than 1, it has reached the
//beginning of the file
return 0;
else
return 1;
}
Linux用途\n
(换行,0x0A)作为新行字符。
Windows/DOS 使用\r\n
(回车符(0x0D)和换行符(0x0A))作为其新行字符。
您可能正在读取 DOS 编码的文件。
这个答案 https://stackoverflow.com/questions/1552749/difference-between-cr-lf-lf-and-cr-line-break-types提供了更多详细信息。
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