我想要一些 JavaScript 代码将 3 个东西作为参数:
- 返回 Promise 的函数。
- 最大尝试次数。
- 每次尝试之间的延迟。
我最终做的是使用for
环形。我不想使用递归函数:这样,即使有 50 次尝试,调用堆栈也不会长 50 行。
这里是打字稿代码版本:
/**
* @async
* @function tryNTimes<T> Tries to resolve a {@link Promise<T>} N times, with a delay between each attempt.
* @param {Object} options Options for the attempts.
* @param {() => Promise<T>} options.toTry The {@link Promise<T>} to try to resolve.
* @param {number} [options.times=5] The maximum number of attempts (must be greater than 0).
* @param {number} [options.interval=1] The interval of time between each attempt in seconds.
* @returns {Promise<T>} The resolution of the {@link Promise<T>}.
*/
export async function tryNTimes<T>(
{
toTry,
times = 5,
interval = 1,
}:
{
toTry: () => Promise<T>,
times?: number,
interval?: number,
}
): Promise<T> {
if (times < 1) throw new Error(`Bad argument: 'times' must be greater than 0, but ${times} was received.`);
let attemptCount: number;
for (attemptCount = 1; attemptCount <= times; attemptCount++) {
let error: boolean = false;
const result = await toTry().catch((reason) => {
error = true;
return reason;
});
if (error) {
if (attemptCount < times) await delay(interval);
else return Promise.reject(result);
}
else return result;
}
}
The delay
上面使用的函数是一个约定的超时:
/**
* @function delay Delays the execution of an action.
* @param {number} time The time to wait in seconds.
* @returns {Promise<void>}
*/
export function delay(time: number): Promise<void> {
return new Promise<void>((resolve) => setTimeout(resolve, time * 1000));
}
澄清一下:上面的代码works,我只是想知道这是否是一种“好的”方法,如果不是,我该如何改进它。
有什么建议吗?在此先感谢您的帮助。