我想解析一组元素TinyXml
输出。本质上,我需要挑选出任何端口元素"portid"
端口属性的状态为"open"
(如下所示为端口 23)。
最好的方法是什么?以下是 TinyXml 输出的(简化)列表:
<?xml version="1.0" ?>
<nmaprun>
<host>
<ports>
<port protocol="tcp" portid="22">
<state state="filtered"/>
</port>
<port protocol="tcp" portid="23">
<state state="open "/>
</port>
<port protocol="tcp" portid="24">
<state state="filtered" />
</port>
<port protocol="tcp" portid="25">
<state state="filtered" />
</port>
<port protocol="tcp" portid="80">
<state state="filtered" />
</port>
</ports>
</host>
</nmaprun>
这将大致做到这一点:
TiXmlHandle docHandle( &doc );
TiXmlElement* child = docHandle.FirstChild( "nmaprun" ).FirstChild( "host" ).FirstChild( "ports" ).FirstChild( "port" ).ToElement();
int port;
string state;
for( child; child; child=child->NextSiblingElement() )
{
port = atoi(child->Attribute( "portid"));
TiXmlElement* state_el = child->FirstChild()->ToElement();
state = state_el->Attribute( "state" );
if ("filtered" == state)
cout << "port: " << port << " is filtered! " << endl;
else
cout << "port: " << port << " is unfiltered! " << endl;
}
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