最近,Wordpress 在 Trac 中添加了您可以使用以下方法按标题获取帖子:
按标题获取页面
而不是直接查询数据库。如果我想获得标题为“我的农场”的帖子,我将如何更改参数以便它搜索帖子(或帖子类型?):
$page_title='乔伊在森林里';
“字符”是一种帖子类型。但不知道如何操作这个。我假设默认返回的是 id,即 $post->ID。不确定如果我使用帖子类型,等效的是什么。
感谢任何人对此的帮助
I wrote 一个函数 http://toscho.de/2010/wordpress-id-anhand-titel-herausfinden/(链接在错误报告中)它正是这样做的:
/**
* Retrieves a post/page/custom-type/taxonomy ID by its title.
*
* Returns only the first result. If you search for a post title
* that you have used more than once, restrict the type.
* Or don’t use this function. :)
* Simple usage:
* $page_start_id = id_by_title('Start');
*
* To get the ID of a taxonomy (category, tag, custom) set $tax
* to the name of this taxonomy.
* Example:
* $cat_css_id = id_by_title('CSS', 0, 'category');
*
* The result is cached internally to save db queries.
*
* @param string $title
* @param string $type Restrict the post type.
* @param string|bool $tax Taxonomy to search for.
* @return int ID or -1 on failure
*/
function id_by_title($title, $type = 'any', $tax = FALSE)
{
static $cache = array ();
$title = mysql_real_escape_string( trim($title, '"\'') );
// Unique index for the cache.
$index = "$title-$type-" . ( $tax ? $tax : 0 );
if ( isset ( $cache[$index] ) )
{
return $cache[$index];
}
if ( $tax )
{
$taxonomy = get_term_by('name', $title, $tax);
$cache[$index] = $taxonomy ? $taxonomy->term_id : -1;
return $cache[$index];
}
$type_sql = 'any' == $type
? ''
: "AND post_type = '"
. mysql_real_escape_string($type) . "'";
global $wpdb;
$query = "SELECT ID FROM $wpdb->posts
WHERE (
post_status = 'publish'
AND post_title = '$title'
$type_sql
)
LIMIT 1";
$result = $wpdb->get_results($query);
$cache[$index] = empty ( $result ) ? -1 : (int) $result[0]->ID;
return $cache[$index];
}
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