子类中的 Yii 模型行为继承了 AR 模型类

我已经实施了一个crypt可以附加到 AR 模型的行为类，以便附加属性将以加密形式存储并以解密字符串形式检索。

class User extends CActiveRecord 
{
    public function behaviors()
    {
        return array(
            'crypt' => array(
            // this assumes that the behavior is in the folder: protected/behaviors/
            'class' => 'application.behaviors.CryptBehavior',
            // this sets that the attributes to be encrypted/decrypted are encryptedfieldname of the model
            'attributes' => array('password'),
            'useAESMySql' => true
           )
        );
    }
}

这工作正常。我也在上我的定制课程Myuser这延伸了User模型来编写我的自定义函数，这样如果我在我的user表和重新生成模型，我不会丢失自己的功能。

如果我移动我的behavior类的函数MyUser, 该行为没有依附并且没有按预期工作.

class MyUser extends User 
{
    public function behaviors()
    {
        return array(
            'crypt' => array(
            // this assumes that the behavior is in the folder: protected/behaviors/
            'class' => 'application.behaviors.CryptBehavior',
            // this sets that the attributes to be encrypted/decrypted are encryptedfieldname of the model
            'attributes' => array('password'),
            'useAESMySql' => true
           )
        );
    }

    public function customfn1()
    {
         //some code goes here...
    }
}

任何帮助，将不胜感激。 参考链接：地穴行为 http://www.yiiframework.com/forum/index.php/topic/26435-aes-encryption/page__view__findpost__p__127764

这是工作解决方案。我需要测试所有场景。感谢@bool.dev 的贡献。

class MyUser extends User 
{
    public static function model($className=__CLASS__)
    {
       return parent::model($className);
    }

    public function behaviors()
    {
        return array(
            'crypt' => array(
            // this assumes that the behavior is in the folder: protected/behaviors/
            'class' => 'application.behaviors.CryptBehavior',
           // this sets that the attributes to be encrypted/decrypted are encryptedfieldname of the model
            'attributes' => array('password'),
           'useAESMySql' => true
          )
       );
    }

   public static function getUserByID($id)
   {
      //validation of $id goes here..

      return MyUser::model()->findByPk($id);
   }
}

在我的控制器中

$userModel = MyUser::getUserByID(1);

在我看来

$userModel->password; //gives me the decrypted password; for easy understanding, i used password field here....