PHP sprintf 转义%

我想要以下输出：-

即将从您的充值账户中扣除 27.59 欧元的 50%。

当我做这样的事情时：-

$variablesArray[0] = '€';
$variablesArray[1] = 27.59;
$stringWithVariables = 'About to deduct 50% of %s %s from your Top-Up account.';
echo vsprintf($stringWithVariables, $variablesArray);

但这给了我这个错误vsprintf() [function.vsprintf]: Too few arguments in ...因为它考虑到% in 50%也用于更换。我该如何逃避它？

与另一个一起逃脱%:

$stringWithVariables = 'About to deduct 50%% of %s %s from your Top-Up account.';