我正在尝试从我的 .txt 文件中删除注释。我的文本文件如下所示:
(* Sunspot data collected by Robin McQuinn from *)
(* http://sidc.oma.be/html/sunspot.html *)
(* Month: 1749 01 *) 58
(* Month: 1749 02 *) 63
(* Month: 1749 03 *) 70
(* Month: 1749 04 *) 56
注释是 (* 和 *) 之间的所有内容。我只需要保留此文件中的 58、63、70 和 56。
我的代码正在删除一些字符,但不正确。我的代码如下所示:
#include <iostream>
#include <vector>
#include <iterator>
#include <algorithm>
#include <fstream>
#include <string>
#include <cctype>
#include <numeric>
#include <iomanip>
using namespace std;
int main() {
int digit = 1;
string filename;
//cout for getting user path
//the compiler parses string literals differently so use a double backslash or a forward slash
cout << "Enter the path of the data file, be sure to include extension." << endl;
cout << "You can use either of the following:" << endl;
cout << "A forwardslash or double backslash to separate each directory." << endl;
getline(cin, filename);
//gets file
ifstream infile{filename};
istream_iterator<char> infile_begin{ infile };
istream_iterator<char> eof{};
vector<char> file{ infile_begin, eof };
for(int i =0; i < file.size(); i++){
if(!isdigit(file[i])) {
if(file[i] != ')') {
file.erase(file.begin(),file.begin()+i);
}
}
}
copy(begin(file), end(file), ostream_iterator<char>(cout, " "));
}
我应该不使用vector.erase()
?我知道这段代码是不正确的。如果是这种情况,更好的解决方案是什么?我知道在 C 中你可以将它写入内存并转到每个位置,这是更好的方法吗?
我首先将所有内容保存为字符串,准备字符串并then安全地将结果推回向量中。
现在我使用 std::regex 来过滤您的文件。但这并不是最简单的。
#include <iostream>
#include <string>
#include <regex>
#include <fstream>
int main(){
std::string file_name;
std::cout << "Enter name/path of the txt file: ";
std::getline(std::cin, file_name);
std::ifstream file(file_name);
std::vector<int> vec; //here save integers
std::string text; //save current line here
std::smatch match; //here the found "comment" get's saved, later to be removed from text
std::regex remove("[\(\*]\.*[\*\)] *"); //the expression to search for
//translation
// _[\(\*] -> (*
// _\.* -> any number of characters
// _[\*\)] -> *)
// _ * -> any number of whitespaces (important to cast to integer)..
while (std::getline(file, text)){ //loop through all lines in file.txt
if (std::regex_search(text, match, remove)){ //if a comment was found
text.erase(text.begin(), text.begin() + match[0].length()); //remove the comment
}
if (!text.empty()) { //empty, line was a pure comment
vec.push_back(std::stoi(text)); //else add integer to list
}
}
std::cout << "The file contains:" << std::endl;
for (int i = 0; i < vec.size(); i++){
std::cout << vec.at(i) << std::endl;
}
return 0;
}
ouput:
Enter name/path of the txt file: file.txt
The file contains:
58
63
70
56
当然,使用std::stoi
仅当没有字符时才有效after整数。嗯,这只是一个想法,当然可以进行高度修改。
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