我想使用 StringTokenizer 搜索字符串，但我正在查找的字符串中有分隔符 - Java

我有一个名为quotes.txt 的外部文件，我将向您展示该文件的一些内容：

1 Everybody's always telling me one thing and out the other.
2 I love criticism just so long as it's unqualified praise.
3 The difference between 'involvement' and 'commitment' is like an eggs-and-ham 
  breakfast: the chicken was 'involved' - the pig was 'committed'.

我用过这个：StringTokenizer str = new StringTokenizer(line, " .'");

这是搜索的代码：

String line = "";
boolean wordFound = false;

while((line = bufRead.readLine()) != null) {
    while(str.hasMoreTokens()) {
       String next = str.nextToken();
       if(next.equalsIgnoreCase(targetWord) {
            wordFound = true;
            output = line;
            break;
       }
    }

    if(wordFound) break;
    else output = "Quote not found";
}

现在，我想搜索字符串"Everybody's" and "it's"在第 1 行和第 2 行中，但它不起作用，因为撇号是分隔符之一。如果我删除该分隔符，那么我将无法搜索"involvement", "commitment", "involved" and "committed"在第 3 行。

我可以用什么合适的代码来解决这个问题？请帮忙并表示感谢。

我建议使用正则表达式（the Pattern class http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html） 而不是StringTokenizer为了这。例如：

final Pattern targetWordPattern =
    Pattern.compile("\\b" + Pattern.quote(targetWord) + "\\b",
                    Pattern.CASE_INSENSITIVE);

String line = "";
boolean wordFound = false;

while((line = bufRead.readLine()) != null) {
    if(targetWordPattern.matcher(line).find()) {
        wordFound = true;
        break;
    }
    else
        output = "Quote not found";
}