Android SearchView 过滤器 ListView

我已在 SherlockAction Bar 中的 SearchView 中实现了搜索过滤器。

当我输入 m 时，我想在下面的列表视图中显示过滤结果，该结果仅以 M 开头，依此类推。但现在它显示随机结果。

public boolean onQueryTextChange(String newText) {
    Log.i("Nomad", "onQueryTextChange");

    if (TextUtils.isEmpty(newText)) {
        adapter.getFilter().filter("");
        Log.i("Nomad", "onQueryTextChange Empty String");
        placesListView.clearTextFilter();
    } else {
        Log.i("Nomad", "onQueryTextChange " + newText.toString());
        adapter.getFilter().filter(newText.toString());
    }
    return true;
}

public boolean onQueryTextSubmit(String query) {
    Log.i("Nomad", "onQueryTextSubmit");
    return false;
}

public boolean onClose() {
    Log.i("Nomad", "onClose");
    return false;
}

将其放入适配器中：

@Override
public Filter getFilter(){
   return new Filter(){

        @Override
        protected FilterResults performFiltering(CharSequence constraint) {
             constraint = constraint.toString().toLowerCase();
             FilterResults result = new FilterResults();

                if (constraint != null && constraint.toString().length() > 0) {
                  List<String> founded = new ArrayList<String>();
                        for(YourListItemType item: origData){
                            if(item.toString().toLowerCase().contains(constraint)){
                                founded.add(item);
                            }
                    }

                        result.values = founded;
                        result.count = founded.size();
                    }else {
                        result.values = origData;
                        result.count = origData.size();
                    }
            return result;


    }
    @Override
    protected void publishResults(CharSequence constraint, FilterResults results) {
           clear();
           for (String item : (List<String>) results.values) {
                 add(item);
           }
    notifyDataSetChanged();

    }

    }
    }

以及适配器的内部构造函数

public MyAdapter(Context context, int layoutResourceId, String[] places) {
        super(context, layoutResourceId, data);
        this.context = context;

        this.data = Arrays.asList(places);
        this.origData = new ArrayList<String>(this.data);

 }