如何在Android TimePicker中设置间隔30分钟的开始时间和结束时间？

我正在 android 中的 DatePicker 和 TimePicker 工作。我正在从服务器获取开始时间和时间。我可以使用以下方式以编程方式设置最大日期和最小日期这个链接 https://stackoverflow.com/questions/6421874/how-to-get-the-date-set-in-the-datepicker-widget-in-android/7961268#7961268

我想在时间选择器中设置最短时间（07:00）和最长时间（10:00）并保持30分钟的间隔。我尝试使用这个链接 https://stackoverflow.com/questions/2580216/android-timepicker-minutes-to-15

我需要的是设置时间选择，最短时间为 07:00，最长时间为 10:00 和时间间隔 07:00,07:30, 08:00 等

这是相同的代码`

  public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);
    TimePicker pn = (TimePicker) findViewById(R.id.tp_powernap);

    pn.setCurrentHour(7);
    pn.setCurrentMinute(0);
    System.out.println("timepicker erstellt");
    pn.setDescendantFocusability(TimePicker.FOCUS_BLOCK_DESCENDANTS);
    System.out.println("Tastatur geblockt");
    pn.setOnTimeChangedListener(StartTimeChangedListener);
    System.out.println("starttimechangedlistener");
    pn.setIs24HourView(false);
}


private TimePicker.OnTimeChangedListener StartTimeChangedListener =
    new TimePicker.OnTimeChangedListener() {

    public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {
        updateDisplay(view, hourOfDay, minute);          
    }
};

private TimePicker.OnTimeChangedListener NullTimeChangedListener =
    new TimePicker.OnTimeChangedListener() {

    public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {

    }
};



private void updateDisplay(TimePicker timePicker, int hourOfDay, int minute) {
    int nextMinute = 0;
    timePicker.setOnTimeChangedListener(NullTimeChangedListener);
    if (minute >= 45 && minute <= 59) 
        nextMinute = 45;  
    else if (minute  >= 30) 
        nextMinute = 30;
    else if (minute >= 15) 
        nextMinute = 15;
    else if (minute > 0) 
        nextMinute = 0; 
    else { 
        nextMinute = 45; 
    }

    if (minute - nextMinute == 1) {
        if (minute >= 45 && minute <= 59) 
            nextMinute = 00; 
        else if(minute  >= 30) 
            nextMinute = 45;
        else if(minute >= 15) 
            nextMinute = 30;
        else if(minute > 0) 
            nextMinute = 15; 
        else { 
            nextMinute = 15; 
        }
    }

    timePicker.setCurrentMinute(nextMinute);

    timePicker.setOnTimeChangedListener(StartTimeChangedListener);

}

仅供参考（这是一个老问题）。可以使用以下 hack 来实现间隔：

Class<?> classForid = Class.forName("com.android.internal.R$id");
Field field = classForid.getField("minute");

NumberPicker mMinuteSpinner = (NumberPicker) timePicker
                    .findViewById(field.getInt(null));
mMinuteSpinner.setMinValue(0);
mMinuteSpinner.setMaxValue((60 / TIME_PICKER_INTERVAL) - 1);
List<String> displayedValues = new ArrayList<String>();
for (int i = 0; i < 60; i += TIME_PICKER_INTERVAL) {
    displayedValues.add(String.format("%02d", i));
}
mMinuteSpinner.setDisplayedValues(displayedValues
                    .toArray(new String[0]));

也可以看看here https://stackoverflow.com/questions/2580216/android-timepicker-minutes-to-15

开始时间和结束时间可以以类似的方式设置，但 AM/PM 标志存在问题。如果您不使用 am/pm 而是始终以 24 小时格式显示时间，您的问题就解决了;-)

        if (startHour != -1 && endHour != -1) {
            Field field = classForid.getField("hour");
            NumberPicker hourSpinner = (NumberPicker) timePicker
                    .findViewById(field.getInt(null));
            hourSpinner.setMinValue(startHour);
            hourSpinner.setMaxValue(endHour);
            List<String> displayedValues = new ArrayList<String>();
            if (timePicker.is24HourView()) {
                for (int i = startHour; i <= endHour; ++i) {
                    displayedValues.add(String.format("%02d", i));
                }
            } else {
                for (int i = startHour; i <= 12; ++i) {
                    displayedValues.add(String.format("%d", i));
                }
                for (int i = 1; i <= endHour % 12; ++i) {
                    displayedValues.add(String.format("%d", i));
                }
            }
            hourSpinner.setDisplayedValues(displayedValues
                    .toArray(new String[0]));
        }