要解密这种形式的加密,您需要获取 Rijndael 版本。可以找到一个here http://wiki.birth-online.de/snippets/python/aes-rijndael。然后,您需要模拟 PHP Mcrypt 模块中使用的密钥和文本填充。他们添加'\0'
将文本和键填充到正确的大小。他们使用 256 位块大小,并且与您提供的密钥一起使用的密钥大小是 128(如果您提供更大的密钥,它可能会增加)。不幸的是,我链接到的 Python 实现一次只能编码一个块。我创建了 python 函数来模拟 Python 中的加密(用于测试)和解密
import rijndael
import base64
KEY_SIZE = 16
BLOCK_SIZE = 32
def encrypt(key, plaintext):
padded_key = key.ljust(KEY_SIZE, '\0')
padded_text = plaintext + (BLOCK_SIZE - len(plaintext) % BLOCK_SIZE) * '\0'
# could also be one of
#if len(plaintext) % BLOCK_SIZE != 0:
# padded_text = plaintext.ljust((len(plaintext) / BLOCK_SIZE) + 1 * BLOCKSIZE), '\0')
# -OR-
#padded_text = plaintext.ljust((len(plaintext) + (BLOCK_SIZE - len(plaintext) % BLOCK_SIZE)), '\0')
r = rijndael.rijndael(padded_key, BLOCK_SIZE)
ciphertext = ''
for start in range(0, len(padded_text), BLOCK_SIZE):
ciphertext += r.encrypt(padded_text[start:start+BLOCK_SIZE])
encoded = base64.b64encode(ciphertext)
return encoded
def decrypt(key, encoded):
padded_key = key.ljust(KEY_SIZE, '\0')
ciphertext = base64.b64decode(encoded)
r = rijndael.rijndael(padded_key, BLOCK_SIZE)
padded_text = ''
for start in range(0, len(ciphertext), BLOCK_SIZE):
padded_text += r.decrypt(ciphertext[start:start+BLOCK_SIZE])
plaintext = padded_text.split('\x00', 1)[0]
return plaintext
可以按如下方式使用:
key = 'MyKey'
text = 'test'
encoded = encrypt(key, text)
print repr(encoded)
# prints 'I+KlvwIK2e690lPLDQMMUf5kfZmdZRIexYJp1SLWRJY='
decoded = decrypt(key, encoded)
print repr(decoded)
# prints 'test'
为了进行比较,以下是具有相同文本的 PHP 输出:
$ php -a
Interactive shell
php > $key = 'MyKey';
php > $text = 'test';
php > $output = mcrypt_encrypt(MCRYPT_RIJNDAEL_256, $key, $text, MCRYPT_MODE_ECB);
php > $encoded = base64_encode($output);
php > echo $encoded;
I+KlvwIK2e690lPLDQMMUf5kfZmdZRIexYJp1SLWRJY=